For this problem you can use the singly linked list code implemented in lab class. Take an integer N (0
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For this problem you can use the singly linked list code implemented in lab class. Take an integer
N (0<N<1000) as input from user. Generate N random values (range: 1-100) and store/delete
them sequentially by implementing the following function:
node* notMoreThanTwo(node *head, int value)
This function will add the number in head if this is first appearance, insert in tail if it is a
duplicate value, and delete the first value if it is in list twice already. For each insertion print %d
inserted and for deletion print %d deleted, where %d is the randomly generated value
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- Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list Develop your solution as follows: First copy the nodes of the current list (self) Create a new list with the copied nodes Loop through the nodes of the new list checking the value field If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L): def clone(self): def clone_node(node): return <... YOUR CODE HERE ...> r = <... YOUR CODE HERE...> return r return L4_class(*args,**kwargs)Write a function with the signature below that returns the sum of the last k elements of a singly linked list that contains integers. int returnSumOfLastKNodes(Node* head, int k) Example: 10 -> 5->8->15->11->9->23 10 represents the head node, returnSumOfLastKNodes(Node* head, 4) will return 58.Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list def show_ids(M, level=0): k = M.first_node while k is not None: print(" "*2*level, id(k)) if (str(k.value.__class__.__name__) == str(M.__class__.__name__)): show_ids(k.value, level+1) k = k.next W=L2(Node(10, Node(L2(Node(14, Node(15, Node(L2(Node(16, Node(17))))))), Node(20, Node(30)))) )show_ids(W) Develop your solution as follows: - First copy the nodes of the current list (self) - Create a new list with the copied nodes - Loop through the nodes of the new list checking the value field - If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L):…
- Write a function that takes a list removal(L), delete from it all the elements whose indicesare divisible by 3. And return the resulting list after removing unwanted elements.Example:>>>removal(['A', 'B', 'C', 'D', 'E'])['B', 'C','E'Considering a singly linked list of integers implementation, assuming that elements of the list are always in ascending order, write a function (find_median) that finds and returns median value. The function cannot scan the list more than ONCE. class SinglyList: class _Node: def __init__(self, e, next): self._element = e self._next = next def __init__(self): self._head = self._tail = None def find_median(self):write a Python function that takes in a list of integers (nums) and finds whether the list consists of any duplicate numbers, the function returns True or False accordingly (Note: this is not a linked list, just a Python list). Function must run in place and cannot use Python’s built-in Set() structure. Make sure to provide the most efficient algorithm in terms of its time and space complexity.
- Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 main.cpp #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main () { // References for MileageTrackerNode objects MileageTrackerNode* headNode; MileageTrackerNode* currNode; MileageTrackerNode* lastNode; double miles; string date; int i; // Front of nodes list headNode = new MileageTrackerNode(); lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read // in data and insert into the linked list // TODO: Call the PrintNodeData() method // to…Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData() method// to print the entire linked list //…Think about the following example: A computer program builds and modifies a linked list like follows:Normally, the program would keep tabs on two unique nodes, which are as follows: An explanation of how to use the null reference in the linked list's node in two common circumstances
- In this task, a skip list data structure should be implemented. You can follow the followinginstructions:- Implement the class NodeSkipList with two components, namely key node and arrayof successors. You can also add a constructor, but you do not need to add anymethod.- In the class SkipList implement a constructor SkipList(long maxNodes). The parameter maxNodes determines the maximal number of nodes that can be added to askip list. Using this parameter we can determine the maximal height of a node, thatis, the maximal length of the array of successors. As the maximal height of a nodeit is usually taken the logarithm of the parameter. Further, it is useful to constructboth sentinels of maximal height.- In the class SkipList it is useful to write a method which simulates coin flip andreturns the number of all tosses until the first head comes up. This number representsthe height of a node to be inserted.- In the class SkipList implement the following methods:(i) insert, which accepts…Please answer it in Python Write a function min_pair that takes a list as an argument and returns the smallest even integer contained in the list. If the list contains no even integers, the function will return None. Example: min_pairs([4, 7, 12, 0, 21, 5]) is 0 min_pairs([9, 3, 1]) is None. min_pair([16, 13, 10, 102, 7, 23]) is 10Imagine we have a linked list as shown below. The ListNodehas two fields: num, an integer, and next, a pointer to the next node. The list is not sorted. Write the definition of a function that calculates and returns the sum of the numbers in the list.