formula Binary? Covalent or Polyatomic ion? Cation variable charge? What? Yes, Gold(II) Name ionic or acid Name? 1.Au(NO,), 2. Ca, (PO,)2 3. Cl,0 4. LiH 5. NaCIO, No ionic Yes, nitrate
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- Help with Part A B and C: Ksp Values: Ionic CompoundFormulaKsp Aluminum hydroxideAl(OH)31.8×10–5 Aluminum phosphateAlPO46.3×10–19 Barium carbonateBaCO35.1×10–9 Barium chromateBaCrO41.2×10–10 Barium fluorideBaF21.0×10–6 Barium hydroxideBa(OH)25×10–3 Barium sulfateBaSO41.1×10–10 Barium sulfiteBaSO38×10–7 Barium thiosulfateBaS2O31.6×10–6 Bismuthyl chlorideBiOCl1.8×10–31 Bismuthyl hydroxideBiOOH4×10–10 Cadmium carbonateCdCO35.2×10–12 Cadmium hydroxideCd(OH)22.5×10–14 Cadmium oxalateCdC2O41.5×10–8 Cadmium sulfide*CdS8×10–28 Calcium carbonateCaCO32.8×10–9 Calcium chromateCaCrO47.1×10–4 Calcium fluorideCaF25.3×10–9 Calcium hydrogen phosphateCaHPO41×10–7 Calcium hydroxideCa(OH)25.5×10–6 Calcium oxalateCaC2O42.7×10–9 Calcium phosphateCa3(PO4)22.0×10–29 Calcium sulfateCaSO49.1×10–6 Calcium sulfiteCaSO36.8×10–8 Chromium(II) hydroxideCr(OH)22×10–16 Chromium(III) hydroxideCr(OH)36.3×10–31 Cobalt(II) carbonateCoCO31.4×10–13 Cobalt(II) hydroxideCo(OH)21.6×10–15 Cobalt(III) hydroxideCo(OH)31.6×10–44…Tu Re-order each list in the table below, if necessary, so that the atoms or lons in it are listed in order of decreasing size. Please don't provide the handwriting solutionExcessive nutrients dumped into waterways can create “algae blooms” that rapidly consume all of the dissolved O2 and trigger production of enough H2S to create “dead zones” like the ones that exist off the coast of Denmark and in the Gulf of Mexico immediately south of the Mississippi River delta. a. Since Group 16 element substitution is a recurring theme in that Group’s chemistry –e.g., oxygen substituting for Se and Te in the production of H2Se and H2Te, respectively –maybe molecular oxygen (O2) could be bubbled into these dead zones and react with the H2S.Write out a balanced chemical equation for the reaction between H2S and O2 to form elemental sulfur (S8) as a product that would precipitate out. b. Using bond dissociation energies, calculate if this reaction would be thermodynamically favorable. c. If your answer to part (b) is “yes”, do you think that simply bubbling O2 into these waters would work? Justify your answer.
- Please answer the last 3 parts: 1)R2BH 2)H2O2,HO-, H2SO4/ HgSO4, and 1) O3 2)H2OThe bonds are stronger in either the TiCl4(g) or the CCl4(g)? What is your reasoning?How do you explain the pattern/trend in the distance between the anion of an acid and H3O+? The acid strength is HCl > HNO3 > HF > HOCl, but I don't understand why the lengths vary like this. Or does it have to do with electronegativity? If it does have to do with electronegativity, why doesn't HF have the shortest length? Or is it because OCl- is more elctronegatvie than F-? Also, does an acid's strength decrease/increase with increasing electronegativity of its conjugate base? When looking at the trend, HI is stronger than HBr, which is stronger than HCl. However, HClO4 is stronger than all of these acids, which I don't understand why.
- What IMF's are present in these molecules? LDF, Double-double forces, H-bond, dipole-dipole, stockholm bonding Please provide an explanation. Thank you.Zinc in its 2+ oxidation state is an essential metal ion for life. Zn2+ is found bound to many proteins that are involved in biological processes, but unfortunately Zn2+ is hard to detect by common chemical methods. Therefore, scientists who are interested in studying Zn2+- containing proteins will frequently substitute Cd2+ for Zn2+ since Cd2+ is easier to detect. Based on the properties from this chapter and their positions in the periodic tables, provide one pro and one con of using Cd2+ as a Zn2+ substitute?Power Index = 178% Heat of explosion (Qv) = 6666kJ/kg Gaseous products detected: CO2, H2O, and N2 (no other gases detected) Total moles of gaseous products detected: 5.3 moles You must determine the molar mass of this compound and draw a reasonable Lewis structure for it. (Hypothetical)
- 2N2O5-------> ?(A) 4NO2{g) + O2 (g)(B) 2NO2 + O6(C) N2O6 + O4im not too sure how to fill this outGroup A: solution conductivity (MS) NaCl 6594 CaCl2 13188 AlCl3 16311 Group B: solution conductivity (MS) HCl 21809 Hc2H3O2 639 H3PO4 8805 For H3PO4, does the subscript "3" of hydrogen in this formula seem to result in additional ions insolution as it did for AlCl3in Group A? Explain.