From the following enthalpy changes, H2 (g) + ½ O2 (g) ® H2O (l) DH° = -285.8 kJ N2O5 (g) + H2O (l) ® 2 HNO3 (l) DH° = -76.6 kJ ½ N2 (g) + 3/2 O2 (g) + ½ H2 (g) ® HNO3 (l) DH° = -174.1 kJ calculate the value of DH° for the reaction 2 N2 (g) + 5 O2 (g) ® 2 N2O5 (g).

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
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From the following enthalpy changes,

                        H2 (g)  +  ½ O2 (g) ®  H2O  (l)                                  DH° = -285.8 kJ

                        N2O5 (g)  +  H2O  (l)   ®   2 HNO3  (l)                      DH° = -76.6 kJ

                        ½ N2 (g)   +   3/2 O2 (g) +  ½ H2 (g) ® HNO3  (l)      DH° = -174.1 kJ

            calculate the value of  DH° for the reaction

                        2 N2 (g)  +  5 O2 (g)  ®   2 N2O5 (g).

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