From the sample data above, perform the following steps. a. Create a regression model that includes all of the independent variables. b. Calculate the variance. c. Calculate the standard error of each parameter's estimate. In your opinion, how precise are the regression coefficients estimated?
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- The National Center for Health Statistics, housed within the U.S. Centers for Disease Control and Prevention (CDC), tracks the number of adults in the United States who have health insurance. According to this agency, the uninsured rates for Americans in 2018 are as follows: 5.1% of those under the age of 18, 12.4% of those ages 18-64, and 1.1% of those 65and older do not have health insurance (CDC website). Approximately 22.8% of Americans are under age 18, and 61.4% of Americans are aged 18-64. Given that the person is an uninsured American, what is the probability that the person is 65 or older (to 3 decimals)?4. The number of passengers (in thousands) for the leading U.S. passenger airlines in 2004 is indicated below. 91,570 86,755 81,066 70,786 55,373 42,400 40,551 21,119 16,280 14,869 13,659 13,417 13,170 12,632 11,731 10,420 10,024 9,122 7,041 6,954 6,406 6,362 5,930 5,585 5,427• Use the data to construct a grouped frequency distribution and a cumulative frequency distribution with a reasonable number of classes and comment on the shape of the distribution using graph.An insurance company classifies its policy holders according to age, sex,and marital status. Of 500 policy holders, it was found out that: 350 weremarried, 240 were under 25, 230 were married men, 110 were marriedand under 25, 100 were men under 25, 40 were married men under 25,and 10 were single women 25 or older. How many policy holders weremen?
- According to the American Management Association, most U.S. companies now test at least some employees and job applicants for drug use. The U.S. National Institute on Drug Abuse claims that about 15% of people in the 18-25 age bracket use illegal drugs. Allyn Clark, a 21 year-old college graduate, applied for a job at the Acton Paper Company, took a drug test, and was not offered a job. He suspected that he might have failed the drug test, even though he does not use drugs. In checking with the company's personnel department, he found that the drug test has 99% sensitivity, which means that only 1% of drug users incorrectly test negative. Also, the test has 98% specificity, meaning that only 2% of nonusers are incorrectly identified as drug users. Allyn felt relieved by these figures because he believed that they reflected a very reliable test that usually provides good results. But is this really true? The accompanying table shows data for Allyn and 1,499 other job applicants. Based…A state highway commission is considering removing the lane that allows people to pay cash for a toll on a toll road and requiring all people who use the toll road to pay with an electronic transponder that is connected to their car. The commission wants to know whether the proportion of people who live in the northern part of the state and are in favor of removing the cash lane is different from the proportion of people who live in the southern part of the state and are in favor of removing the cash lane. Independent random samples are selected from the northern and southern parts of the state. The table summarizes the responses of those surveyed. Northern Southern Total Remove Cash Lanes 112 98 210 Keep Cash Lanes 89 105 194 Total 201 203 404 Which of the following is closest to the pp-value of the appropriate test to investigate whether the proportion of people living in the northern part of the state who are in favor of removing the cash lane is different from…Whattheareaofthefigurewhatthehelldj
- Household Paper Plastic 1 15.09 9.11 2 16.39 9.7 3 6.33 3.86 4 9.45 3.02 5 6.98 2.65 6 8.72 9.2 7 11.42 12.81 8 6.67 6.09 9 6.16 5.88 10 16.08 14.36 11 13.61 8.95 12 11.08 12.47 13 9.41 3.36 14 6.44 8.4 15 12.43 8.57 16 7.98 6.09 17 3.27 0.63 18 13.31 19.7 19 7.72 3.86 20 12.73 14.83 21 6.96 7.6 22 17.65 11.26 23 14.33 6.43 24 2.8 5.92 25 9.83 6.26 26 9.55 9.2 27 11.36 10.25 28 7.57 5.92 29 12.32 11.17 30 20.12 18.35#9;review ch7Date DJIA S&P 500 January 6 12,360 1,278 January 13 12,422 1,289 January 20 12,720 1,287 January 27 12,660 1,234 February 3 12,862 1,267 February 10 12,801 1,243 February 17 12,950 1,262 February 24 12,983 1,378 March 2 12,978 1,301 March 9 12,922 1,345 March 16 13,233 1,404 March 23 13,081 1,404 March 30 13,212 1,408 April 5 13,060 1,398 April 13 12,850 1,203
- the internal revenue Service (irS) provides a toll-free help line for taxpayers to call inand get answers to questions as they prepare their tax returns. in recent years, the irShas been inundated with taxpayer calls and has redesigned its phone service as well asposted answers to frequently asked questions on its website (the Cincinnati Enquirer,January 7, 2010). according to a report by a taxpayer advocate, callers using the newsystem can expect to wait on hold for an unreasonably long time of 12 minutes beforebeing able to talk to an irS employee. Suppose you select a sample of 50 callers afterthe new phone service has been implemented; the sample results show a mean waitingtime of 10 minutes before an irS employee comes on the line. based upon data from pastyears, you decide it is reasonable to assume that the standard deviation of waiting timeis 8 minutes. using your sample results, can you conclude that the actual mean waitingtime turned out to be significantly less than the…Company Competitor 1383 1153 2022 1067 2429 1296 901 1406 2219 1254 1896 1335 1910 1204 1539 1076 2048 1246 2881 1098 2395 1258 1349 955 2052 954 2675 1363 1588 1022 2704 1155 3148 1807 2822 1295 2217 1116 2260 1323 3040 1326 3137 1107 2977 1163 2599 1254 2412 1017 3187 938 2598 1270 2995 1042 3046 1318 3858 1497 2438 750 3243 1380 2764 1053 2944 932 3324 1097 2797 1193 3914 1271 2766 843 2273 780 3052 1095 3202 1290 3672 937 3957 1390 3274 1056 3788 1235 3502 1235 2942 999 3078 1066 3196 641 3141 1322 3579 1289 3895 1060 above is the excel data, please solve the excel part with formulas and explanation, thanksFollowing are the number of miles traveled for 30 randomly selected business flights within the United States during 1999. 1605, 670, 840, 976, 857, 1197, 1979, 1265, 1010, 704,1146, 1673, 1571, 687, 704, 2081, 2013, 1571, 1894, 1724,1248, 1843, 1163, 1146, 1826, 1095, 500, 755, 1214, 1877 a) Use the data to obtain a point estimate for the population mean number of miles traveled per business flight, μμ, in 1999.Note: The sum of the data is 38834.x¯=x¯= b) Determine a 95.44% confidence interval for the population mean number of miles traveled per business flight in 1999. Assume that σ=450σ=450 miles. Confidence interval: ( , ). c) Must the number of miles traveled per business flight in 1999 be exactly normally distributed for the confidence interval that you obtained in part (b) to be approximately correct? d) What theorem helped you answer part (c)?