Functional Soluble Soluble in Soluble in Soluble in Specific Compound Group in Water? 1 M HCI? 1 M NaOH? 1 M NaHCO3? Amine & m-Aminoacetophenone No Yes No No Carbonyl Cholesterol OH Group No No No No 4-t-Butylphenol ОH Group No Yes No No Benzoic acid COOH Group No No Yes Yes
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- Explain the following 1. difference between pka1 and pka2 for carboxylic acids of the type HOOC(CH2)COOH decreases as n increases 2. Arrange oxalic,manolic,succinic, and glutanic acids in order of activity( first ionisation). How do you account for this order?The Kb for dimethylamine, CH3NH2, at 25oC is 4.0×10-4. What’s the Ka of its conjugate acid?SHOW COMPLETE SOLUTIONS Q3. Which isolate has A260/280 ratio of above 2.0?
- Ammonia (NH3) is a weak base that under acidic conditions becomes protonated to the ammonium ion in thefollowing reaction:NH3 + H+ → NH4 +NH3 freely permeates biological membranes, including thoseof lysosomes. The lysosome is a subcellular organelle witha pH of about 4.5–5.0; the pH of cytoplasm is about 7.0.What is the effect on the pH of the fluid content of lysosomes when cells are exposed to ammonia? Note: Ammonium (NH4 +) does not diffuse freely across membranes.What is Kb for the equilibrium rreacton: CN- + H2O <=> HCN + OH- ? Ka value of 6.23 x10-10On the axes below, sketch the graphs which show the result of adding: 0.1M NaOH to 25cm3 of 0.1M ethanoic acid. 0.1M NaOH to 25cm3 of 0.1M H2SO4
- Kindy provide solution. Thanks1. The conversion of the concentrations into the required expression is as follows: Concentration given Expression required 0.5% NaCl molarity 1 mM of KBr mg/ml 5 mg/100 ml paracetamol Molarity 0.15 N H2SO4 g/litre 0.5% ethanol/water (w/v) ppm 2. 0.641 g of a semi-synthetic alkaloid was dissolved in 25 ml of 1% w/v acetic acid and was analysed directly by HPLC. The solution was found to contain 1.42 mg/100 ml of an impurity. What is the level of impurity in % w/w and ppm? 3. Calculate the pH of a buffer system made by dissolving 1.2 g of acetic acid and 0.82 g of sodium acetate in 500 ml of distilled water (pKa of acetic acid = 4.7) 0.641 g of a semi-synthetic alkaloid was dissolved in 25 ml of 1% w/v acetic acid and was analysed directly by HPLC. The solution was found to contain 1.42 mg/100 ml of an impurity. What is the level of impurity in % w/w and ppm?Give typed full explanation not a single word hand written otherwise leave it Calculate the pOH of a 9.5 x 10-2mol L-1solution of ascorbic acid (Ka1 = 7.9 x 105, Ka2= 2.5 x 10-12). Show your work evaluating the validity of an appropriate simplifying assumption.