Give a paragraph form of proof.X =2AMNQ=M=Let x be the semiperimeter of AMNQ. Using the given side lengths (in terms of s and a), the semiperimeter is(1Simplifying gives x = 5 + a=SGiven:Prove:=28 + 2aXXlengths (in terms of s and a) along with the semiperimeter x, the area AMNQ of the triangle is given by the following.AMNQ = √√x(x - 5)(x - 5)(x − ( [Substituting the expression found for x into the equation and simplifying gives the following.)(a + 5) -- s) − s)((a +(a + s) - s2a5+aAMNQ(Note: s > a.)√a².isosceles AMNQ with QM = QNs and MN = 2a= a√√√√ s² - a²a²(s + a)(a + s).a.a.2 [SNXs²_a²5-a5-a. Using Heron's Formula with the given sidex - 2a:) - s) ((a+s) - 2a)

We will find the area of given isosceles triangle.

Give a paragraph form of proof. X = (1 2 AMNQ = M = S Let x be the semiperimeter of AMNQ. Using the given side lengths (in terms of s and a), the semiperimeter is 1₂) Simplifying gives x = 5 + a X X lengths (in terms of s and a) along with the semiperimeter x, the area AMNQ of the triangle is given by the following. = Given: Prove: 28 + 2a 2a AMNQ = √√x(x - 5)(x - 5)(x − ( [ Substituting the expression found for x into the equation and simplifying gives the following. )(a + 5) - (a + s) 5+a AMNQ (Note: s > a.) isosceles AMNQ with QM = QNs and MN = 2a = a√√√√ s² - a² a²(s + a) (a + s).a.a. (E S X N 5-a 5-a x - 2a . Using Heron's Formula with the given side X − s)((a + s) − s)((a + s) − 2a −

Give a paragraph form of proof. X = (1 2 AMNQ = M = S Let x be the semiperimeter of AMNQ. Using the given side lengths (in terms of s and a), the semiperimeter is 1₂) Simplifying gives x = 5 + a X X lengths (in terms of s and a) along with the semiperimeter x, the area AMNQ of the triangle is given by the following. = Given: Prove: 28 + 2a 2a AMNQ = √√x(x - 5)(x - 5)(x − ( [ Substituting the expression found for x into the equation and simplifying gives the following. )(a + 5) - (a + s) 5+a AMNQ (Note: s > a.) isosceles AMNQ with QM = QNs and MN = 2a = a√√√√ s² - a² a²(s + a) (a + s).a.a. (E S X N 5-a 5-a x - 2a . Using Heron's Formula with the given side X − s)((a + s) − s)((a + s) − 2a −

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter6: Circles

Section6.3: Line And Segment Relationships In The Circle

Problem 39E: The center of a circle of radius 2 in. is at a distance of 10 in. from the center of a circle of...

See similar textbooks

Similar questions

The center of a circle of radius 2 in. is at a distance of 10 in. from the center of a circle of radius length 3 in. To the nearest tenth of an inch, what is the approximate length of a common internal tangent? Use the hint provided in Exercise 38. HINT: use similar triangles to find OD and DP. Then apply the Pythagorean Theorem twice.
The center of a circle of radius 2 inches is at a distance of 10 inches from the center of a circle of radius length 3 inches. To the nearest tenth of an inch, what is the approximate length of a common internal tangent? Use the hint provided in Exercise 38. HINT: use similar triangles to find OD and DP. Then apply the Pythagorean Theorem twice.
In Exercises 25 and 26, give a paragraph form of proof. Provide drawings as needed. Given: Isosceles MNQ with QM=QN=s and MN=2a Prove: AMNQ=as2-a2 NOTE: sa.
Given : In the figure, a=e=66. Also, YZZW. If YW=14.3 in. and YZ=7.8 in., find the perimeter of XYW to the nearest tenth of an inch.
From the veranda of a beachfront hotel, Manny is searching the seascape through his binoculars. A ship suddenly appears on the horizon. If Manny is 80ft above the earth, how far is the ship out at sea? HINT: See Exercise 27 and note that 1mi=5280ft. An airplane reaches an altitude of 3mi above the earth. Assuming a clear day and that a passenger has binoculars, how far can the passengers see? HINT: The radius of the earth is approximately 4000 mi.
For Exercise 41 to 44, 1 ft3 of liquid corresponds to 7.5 gallons of the liquid. The gasoline tank on an automobile is box-shaped with dimensions of 24 in. by 20 in. by 9 in. What is the capacity of the automobiles fuel tank in gallons?
In Exercises 44 and 45, use the formula from Exercise 43. Similar triangles were used to find h and H. A container of yogurt has the shape of a frustum of a cone. With the lower base having diameter length 6 cm and the upper base having diameter length 8 cm, the volume of such a container 7.5 cm tall can be determined by using H=30 cm and h=22.5 cm. Find its volume. A frustum of a cone is the portion of the cone bounded between the circular base and a plane parallel to the base. With dimensions are indicated, show that the volume of the frustum of the cone is V=13R2H13rh2
Given: ABC, whose sides are 13 in., 14 in., and 15 in. Find: a BD, the length of the altitude to the 14-in. side HINT: USE the Pythagorean Theorem twice. b The area of ABC, using the result from part a Exercises 39, 40
Given: Regular pentagon JKLMN not shown with diagonals LNandKN. Find: mLNK
If MNPQ is a rhombus, which formula from this section should be used to calculate its area? Exercise 46