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- Mass solute needed to prepare 0.500L of 0.2 M NaCO3 from a solid NaCO3 with a purity of 92.0wt%The first goal is to make the oxalic acid standard solution. You measure 1.5232 g of oxalic acid on an analytical balance, add it to a 250-mL volumetric flask and add deionized H2O to a final volume of 250.0 mL. Molar mass of H2C2O4•2H2O = 126.07 g/mol Mass of H2C2O4•2H2O = 1.5232g Volume of H2C2O4•2H2O solution = 250.0mL What is the Molarity H2C2O4 standard solution ?30.0 mL of 0.400 M Zn²⁺ is mixed with 100.0 mL of 0.200 M F⁻ (Ksp ZnF₂ = 0.030). In the mixture you would observe
- You have to make 50 mL of 0.05M HCl from a 10M HCl stock solution, but the only measuring devices available are 100mL graduated cylinders and 10mL serological pipets. How could you accurately make the dilute HCl solution (clearly explain)?In how much volume of diluted sulfuric acid should you dissolve a multivitamin tablet of approximately 1700 mg of Vitamin C to back analyze 10.00 mL of that solution, with 25.00 mL of 0.01 M KIO3 and 0.04 M thiosulfate to use approximately 8-10 mL of titrant ? You have 25, 50, 150, 250 and 500 mL flasks.The first goal is to make the oxalic acid standard solution. You measure 1.5232 g of oxalic acid on an analytical balance, add it to a 250-mL volumetric flask and add deionized H2O to a final volume of 250.0 mL. Molar mass of H2C2O4•2H2O = 126.07 g/mol Mass of H2C2O4•2H2O = 1.5232g what is the Number of moles of H2C2O4•2H2O?
- What is the percentage purity of acetic acid if 2.6 grams required 32.5 ml of 0.994 N NaOH solution to reach the endpoint? Does it conform to USP requirements for acetic acid 3%-6%?3. Analysis of a mixture consisting of NaOH + Na2CO3 + inert matter gives the following data: 10.00 g. Its aqueous solution is diluted to 250.0 mL and two separate 25.00 mL sample portions are titrated. With one portion, an end point with phenolphthalein is obtained in cold solution, with 44.52 mL of 0.5000 N HCI. The other portion requires 46.53 mL of the acid for an end point with methyl orange. Calculate the percentage composition of the original sample.A 18 g of unknown organic sample was dissolve in 756 mL of benzene. The boiling point of benzene was increased by 3.36oC. As the first step of analysis, determine the moecular weight of the unknow sample? Kb of benzene= 2.64oC/m Bb of benzene = 80.09 oC density of benzene = 0.874 g/mL at 25 °C Answer in whole number, no units required.
- 15 g of unknown organic sample was dissolve in 575 mL of Dicloromethane (DCM). The boiling point of benzene was increased by 3.40oC. Determine the molecular weight of the unknown sample? Kb of DCM = 2.42oC/m Bb of benzene = 39.6 oC density of benzene = 1.33 g/mL at 25 °CA 2.0 g of MgCO3 was dissolved and diluted to exactly 500-mL volumetric flask. If 50-mL aliquot was used in the analysis, what is the weight of MgCO3 present in the aliquot sample1. Calculate the mass required to prepare a 250 mL 3 M NaCl in water.Mass = M x MM x V 10002. Calculate how to prepare the following dilutions, ½, ¼, 1/8 and 1/16 of the initial concentration.There is a helpful equation that is used to determine how much stock solution and how much diluent to combine to get the final solution of a desired concentration