Given = 3.0 M Ca(oH)2 & 2.5LLooking For =g Ca (OH)2(3.0M)X2.5 L)mol= 7.5 mol CaloH )2M= molmol = M × L =Calx40.08 = 40.08| x 16.0 0 = 1le.00I x 1.01 1.%3D57.09 g/mol CacoH)27.5 mol CaloH)z 57.09 gCa(ott)428.189I mol Ca(oH)2CaloH2The student got the answer wrong. Identify the error, explain the mistake in detailand fix it by providing the correct answer.

The weight of Ca(OH)2 has to be given,

Given= 3.0 M Ca(oH)2 & 2.5L Looking For = g CacOH). M × L = (3.0MX2.5 L) mol= 7.5 mol CaloH )2 M= mol Cal x 40.08 = 40.08 | x 16.0 0 = 1le.00 I x 1.01 1.0 57.09 g/mol Calон), 7.5 mol CaloH)z 57.09gCa(ott428.18g I moi Calot) z CalOH 2 he student got the answer wrong. Identify the error, explain the mistake in detail nd fix it by providing the correct answer.

Given= 3.0 M Ca(oH)2 & 2.5L Looking For = g CacOH). M × L = (3.0MX2.5 L) mol= 7.5 mol CaloH )2 M= mol Cal x 40.08 = 40.08 | x 16.0 0 = 1le.00 I x 1.01 1.0 57.09 g/mol Calон), 7.5 mol CaloH)z 57.09gCa(ott428.18g I moi Calot) z CalOH 2 he student got the answer wrong. Identify the error, explain the mistake in detail nd fix it by providing the correct answer.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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