Given a computer with a memory system having a40_bit address, a cache consisting of 8192 blocks each is 32 words. For the following cache types: Direct Mapped (DM)., Fully_ associative (FA), Two_ way set associative (2_way), Four_ way set associative (4_way), Eight_way set associative (8_way), calculate the following values as specified. (Use paper and pencil to do needed calculations and write only the final answer in the given blank space). 1) DM: The size of the index field - Blank 1bits 2) 2_way: The size of the index field -Blank 2bits 3) 4_way: The size of the index field -Blank 3bits 4) 8_way: The size of the index field =Blank 4bits 5) The size of the offset field - Blank 5bits 6) DM: The size of the tag field -Blank 6bits 7) 2_way: The size of the tag field =Blank 7bits 8) 4_way: The size of the tag field =Blank 8bits 9) 8_way: The size of the tag field =Blank 9bits 10) FA: The size of the tag field -Blank 10bits

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Given a computer with a memory system having a40_bit address, a cache consisting of 8192 blocks each is 32 words. For the
following cache types: Direct Mapped (DM), Fully_ associative (FA), Two_way set associative (2_way), Four_way set associative
(4_way), Eight_way set associative (8_way), calculate the following values as specified.
(Use paper and pencil to do needed calculations and write only the final answer in the given blank space).
1) DM: The size of the index field = Blank 1bits
2) 2_way: The size of the index field =Blank 2bits
3) 4_way: The size of the index field =Blank 3bits
4) 8_way: The size of the index field =Blank 4bits
5) The size of the offset field = Blank 5bits
6) DM: The size of the tag field =Blank 6bits
7) 2_way: The size of the tag field =Blank 7bits
8) 4_way: The size of the tag field =Blank 8bits
9) 8_way: The size of the tag field =Blank 9bits
10) FA: The size of the tag field =Blank 10bits
Transcribed Image Text:Given a computer with a memory system having a40_bit address, a cache consisting of 8192 blocks each is 32 words. For the following cache types: Direct Mapped (DM), Fully_ associative (FA), Two_way set associative (2_way), Four_way set associative (4_way), Eight_way set associative (8_way), calculate the following values as specified. (Use paper and pencil to do needed calculations and write only the final answer in the given blank space). 1) DM: The size of the index field = Blank 1bits 2) 2_way: The size of the index field =Blank 2bits 3) 4_way: The size of the index field =Blank 3bits 4) 8_way: The size of the index field =Blank 4bits 5) The size of the offset field = Blank 5bits 6) DM: The size of the tag field =Blank 6bits 7) 2_way: The size of the tag field =Blank 7bits 8) 4_way: The size of the tag field =Blank 8bits 9) 8_way: The size of the tag field =Blank 9bits 10) FA: The size of the tag field =Blank 10bits
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