Electric Machine; Check image, all question there.The efficiency of 25 kW, 350 V round rotor synchronous motor is 95%. Since the motor circuit parameters are given as r=0.075Ω and X. =1.75 Ω, find the followings for motor with 85% load and cos(Ø) = 0.8 (end) in operation.a)Calculate the current drawn by the motor from the network b)Calculate the induced pole whell voltage (Ef) EAVa+VeL E,VEFig. Equivalent Circuit of Synchronous MachineThe efficiency of a 25 kW, 350 V round rotor synchronous motor is 95 %. Since the motor circuit parameters are given as r = 0.075N andX, = 1.75N, find the followings for motor with 85 % load and cos(4) = 0.8 (end) in operation.a) Calculate the current drawn by the motor from the networkb)Calculate the Induced pole wheel voltage (Ef)O a. Case a : 59.799 ACase b: 207.504 < –10.6469° VO b. Case a : 46.1229 ACase b: 163.308 < -22.5005° VO c. Case a : 29.799 ACase b: 105.54 < –10.6469° VC.O d. Case a : 29.799 ACase b: 285.504 < -15.6469° VO e. Case a : 59.899 ACase b: 275.504 < -10.6469° V

An AC motor is an electrical machine which takes AC electrical input energy and produces mechanical…

Answered: given as r=0.075Ω and X. =1.75 Ω, find…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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Electric Machine; Check image, all question there.

The efficiency of 25 kW, 350 V round rotor synchronous motor is 95%. Since the motor circuit parameters are given as r=0.075Ω and X. =1.75 Ω, find the followings for motor with 85% load and cos(Ø) = 0.8 (end) in operation.

a)Calculate the current drawn by the motor from the network

b)Calculate the induced pole whell voltage (Ef)

E
AV
a
+
Ve
L E,
V
E
Fig. Equivalent Circuit of Synchronous Machine
The efficiency of a 25 kW, 350 V round rotor synchronous motor is 95 %. Since the motor circuit parameters are given as r = 0.075N and
X, = 1.75N, find the followings for motor with 85 % load and cos(4) = 0.8 (end) in operation.
a) Calculate the current drawn by the motor from the network
b)Calculate the Induced pole wheel voltage (Ef)
O a. Case a : 59.799 A
Case b: 207.504 < –10.6469° V
O b. Case a : 46.1229 A
Case b: 163.308 < -22.5005° V
O c. Case a : 29.799 A
Case b: 105.54 < –10.6469° V
C.
O d. Case a : 29.799 A
Case b: 285.504 < -15.6469° V
O e. Case a : 59.899 A
Case b: 275.504 < -10.6469° V

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