Given H0 : =μ23, Ha : ≠μ23, and =P0.029 . Do you reject or fail to reject H0
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- If the value of Cronbach’s alpha is 0.07, it means ___________; a. Research instrument is not reliable b. Research instrument is internally consistent c. Data is reliable d. Data is internally consistentDr. Stevenson reported the following in a journal: “F (4, 106) = 10.09, p = .04.” Should Dr. Stevenson state that there are significant differences among the variable means at a .01 alpha level?andres asked if there is a relationship between the quality of sneakers worn by a sample of 20 volleyball players and their average number of point scored per game. he computed r= +.21 and immediately claimed he had evidence that better-quality sneakers are related to better performance (a) is his claim correct? why? (b) what are Ho and Ha? (c) with alpha=.05, what is rcrit ?
- In a test of H0: p = .43 versus Ha: p ≠ .43, a sample of size 1500 leads to a p-value of 0.087. Which of the following must be true if a = 0.05? A. The Ho should be rejected at the 5% level B. The Ho should fail to be rejected at the 5% level C. The Ho should be accepted at the 5% levelThe desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with ? = 0.32 and that x = 5.21. (Use ? = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5?State the appropriate null and alternative hypotheses. H0: ? = 5.5Ha: ? ≠ 5.5H0: ? = 5.5Ha: ? ≥ 5.5 H0: ? = 5.5Ha: ? < 5.5H0: ? = 5.5Ha: ? > 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the desired percentage.Reject the null hypothesis. There is sufficient evidence…Dr. Romanoff reported the following in a journal: “F (5, 106) = 10.09, p = .04.” Should Dr. Romanoff state that there are significant differences among the variable means at a .05 alpha level?
- Listed below are the lead concentrations in muμg/g measured in different traditional medicines. Use a 0.010.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 1515 muμg/g. Assume that the lead concentrations in traditional medicines are normally distributed. 1212 22.522.5 88 33 9.59.5 22.522.5 12.512.5 13.513.5 10.510.5 10.510.5 What are the null and alternative hypotheses? A. Upper H 0H0: muμequals=1515 muμg/g Upper H 1H1: muμless than<1515 muμg/g Your answer is correct. B. Upper H 0H0: muμequals=1515 muμg/g Upper H 1H1: muμgreater than>1515 muμg/g C. Upper H 0H0: muμgreater than>1515 muμg/g Upper H 1H1: muμless than<1515 muμg/g D. Upper H 0H0: muμequals=1515 muμg/g Upper H 1H1: muμnot equals≠1515 muμg/g Determine the test statistic. negative 1.33 (Round to two decimal places as needed.)…A treatment is administered to a sample selected from a population with a mean of u = 34 and a standard deviation of o = 8. After treatment, the effect size is measured by computing Cohen’s d, and a value of d = 0.00 is obtained. Based on this information, what is the mean for the treated sample?If the test of H0: = 19 against Ha: ≠ 19 based on an SRS of 15 observations from a Normal populationproduces the statistic of t = –1.75. The P-value is
- Listed below are the lead concentrations in muμg/g measured in different traditional medicines. Use a 0.010.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 1717 muμg/g. Assume that the lead concentrations in traditional medicines are normally distributed. 1010 13.513.5 16.516.5 19.519.5 2121 13.513.5 3.53.5 22.522.5 1313 3.53.5 What are the null and alternative hypotheses? A. Upper H 0H0: muμequals=1717 muμg/g Upper H 1H1: muμless than<1717 muμg/g B. Upper H 0H0: muμequals=1717 muμg/g Upper H 1H1: muμgreater than>1717 muμg/g C. Upper H 0H0: muμequals=1717 muμg/g Upper H 1H1: muμnot equals≠1717 muμg/g D. Upper H 0H0: muμgreater than>1717 muμg/g Upper H 1H1: muμless than<1717 muμg/g Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to…Assume we wanted to show that the true proportion of virginica iris seeds that fail to germinate is less than 20%. Let's say we tested at an alpha of 0.05, and found a p-vale of 0.082. Which of the following would be an appropriate conclusion and interpretation? A) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state we have insufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. B) With an alpha of 0.05, and a p-value of 0.0082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. C) With an alpha of 0.05, and a p-value of 0.082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. D) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state…given H a: u>85 and P=0.007. do you reject or fail to reject H0 at the 0.01 level of significance?