Given the balanced chemical equation: Fe(s) +2 HCI(aq) FeCl2(aq) + H2(3) AHrxn ?? A sample of 0.93 g of Fe metal is combined with excess HCI to make 200 g of solution in a calorimeter and allowed to react completely. If the temperature of the solution rises from 25.0 °C to 29.6 °C, find AHrxn in kJ for this reaction. (Cs of soln = 4.184 J/g °C) (1 kJ=1000 J) Csoln, msoln AT 9soln 9rxn AHxn AHan = Arxn mol of Fe q=m xc x AT 9 rxn = -9soln %3D Include the sign for your value. Round and report your answer to an integer without decimal place.

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter5: Thermochemistry
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Given the balanced chemical equation:
Fe(s) +2 HCI(aq) → FeCl2(aq) + H2(3)
AHrxn ??
A sample of 0.93 g of Fe metal is combined with excess HCI to make 200 g of solution in a
calorimeter and allowed to react completely. If the temperature of the solution rises from 25.0 °C
to 29.6 °C, find AHrxn in kJ for this reaction. (Cs of soln = 4.184 J/g °C) (1 kJ=100O J)
Csoln, msoln, AT
9soln
qrxn
q = m x c x AT.
Arxn
mol of Fe
%D
9rxn =-soln
Include the sign for your value. Round and report your answer to an integer without decimal place.
Transcribed Image Text:Given the balanced chemical equation: Fe(s) +2 HCI(aq) → FeCl2(aq) + H2(3) AHrxn ?? A sample of 0.93 g of Fe metal is combined with excess HCI to make 200 g of solution in a calorimeter and allowed to react completely. If the temperature of the solution rises from 25.0 °C to 29.6 °C, find AHrxn in kJ for this reaction. (Cs of soln = 4.184 J/g °C) (1 kJ=100O J) Csoln, msoln, AT 9soln qrxn q = m x c x AT. Arxn mol of Fe %D 9rxn =-soln Include the sign for your value. Round and report your answer to an integer without decimal place.
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