Given the following data:C2H2(g) + 5/2 O2(g) --> 2CO2(g) + H2O(l)      ΔH= -1300.kJC(s) + O2(g) --> CO2(g)                                   ΔH= -394kJH2(g) + 1/2O2(g) --> H2O(l)                                 ΔH= -286kJUse Hess’s Law to calculate ΔH for the reaction2C(s) + H2(g) --> C2H2(g)

Question
Asked Nov 7, 2019

Given the following data:

C2H2(g) + 5/2 O2(g) --> 2CO2(g) + H2O(l)      ΔH= -1300.kJ

C(s) + O2(g) --> CO2(g)                                   ΔH= -394kJ

H2(g) + 1/2O2(g) --> H2O(l)                                 ΔH= -286kJ

Use Hess’s Law to calculate ΔH for the reaction

2C(s) + H2(g) --> C2H2(g)

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Step 1

The given equation are with their enthalpy of reaction are

AH=-1300. kJ
C2H2(g)+5/2 O2(g) --> 2CO2(g) +H20(1)
(1)
C(s) +O2(g)CO2(g)
AH= -394KJ
(2)
H2(g) 1/202(g) > H20()
AH= -286KJ
(3)
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AH=-1300. kJ C2H2(g)+5/2 O2(g) --> 2CO2(g) +H20(1) (1) C(s) +O2(g)CO2(g) AH= -394KJ (2) H2(g) 1/202(g) > H20() AH= -286KJ (3)

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Step 2

The reaction to be obtained is

2C(s)+H2(g)-2H2(g)
(4)
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2C(s)+H2(g)-2H2(g) (4)

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Step 3

To obtain the given reaction

Eq(4)= eq(...

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