Asked Nov 12, 2019

Given the following equation: 2 NaClO3 ➞ 2 NaCl + 3 O2. How many grams of NaCl are produced when 80.0 grams of O2 are produced? (Molecular mass of oxygen: 16 g/mol) (Molar mass of sodium chloride: 58.45 g/mol)


Expert Answer

Step 1


The mass of oxygen produced =80.0g

The equation according to which reaction takes place


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2 NaClO3 2 NaCl+ 3 O2

Step 2

The moles of NaCl produced


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given mass no of moles of oxygen produced= molar mass 80.0g 16.0g/mol =5.0moles 3 moles of oxygen are produced with 2 moles of NaCi 5 moles of oxygen are produced with x5 moles of NaCl 3 3.33 moles of NaCl

Step 3

Mass of NaCl p...


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mass of NaCl produced-moles x molar mass =3.33 x 58.45g = 194.64g


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