Question
Asked Nov 12, 2019
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Given the following equation: 2 NaClO3 ➞ 2 NaCl + 3 O2. How many grams of NaCl are produced when 80.0 grams of O2 are produced? (Molecular mass of oxygen: 16 g/mol) (Molar mass of sodium chloride: 58.45 g/mol)

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Expert Answer

Step 1

Given

The mass of oxygen produced =80.0g

The equation according to which reaction takes place

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2 NaClO3 2 NaCl+ 3 O2

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Step 2

The moles of NaCl produced

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given mass no of moles of oxygen produced= molar mass 80.0g 16.0g/mol =5.0moles 3 moles of oxygen are produced with 2 moles of NaCi 5 moles of oxygen are produced with x5 moles of NaCl 3 3.33 moles of NaCl

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Step 3

Mass of NaCl p...

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mass of NaCl produced-moles x molar mass =3.33 x 58.45g = 194.64g

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Quantitative analysis

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