Given the following equation: 2PBS(s) + 302(g) → 2PbO(s) + 2SO2(g) If 100 g PbS(s) react with 100 g O2(g) and only 21 g PbO(s) is formed, which reagent is the limiting reagent and what is the percentage yield of the reaction? (Given: Mphs = 239.3 g.mol1; Mo2 = 32 g.mol1; MpbO = 223.2 g.mol 1). %3D %3D

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.83PAE
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Given the following equation:
2PBS(s) + 302(g)
2PbO(s) +
2SO2(g)
If 100 g PbS(s) react with 100 g
O2(g) and only 21 g PbO(s) is
formed, which reagent is the
limiting reagent and what is the
percentage yield of the reaction?
(Given: Mphs = 239.3 g.mol1; Mo2
= 32 g.mol1; Mpho = 223.2 g.mol
1).
%3D
%3D
%3D
Transcribed Image Text:Given the following equation: 2PBS(s) + 302(g) 2PbO(s) + 2SO2(g) If 100 g PbS(s) react with 100 g O2(g) and only 21 g PbO(s) is formed, which reagent is the limiting reagent and what is the percentage yield of the reaction? (Given: Mphs = 239.3 g.mol1; Mo2 = 32 g.mol1; Mpho = 223.2 g.mol 1). %3D %3D %3D
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