Given the following thermochemical equations, Equation 1:     4B(s) + 3O2(g) → 2B2O3(s)                         ∆Ho= -2543.8 kJ Equation 2:     H2 (g) + ½ O2(g) → H2O (g)                        ∆Ho= -241.8 kJ Equation 3:     B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)   ∆Ho= -2032.9 kJ Which of the following statement/s is/are true in calculating the ∆Ho for the decomposition of B2H6 into its elements? Check all that apply.

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
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Given the following thermochemical equations,

Equation 1:     4B(s) + 3O2(g) → 2B2O3(s)                         ∆Ho= -2543.8 kJ
Equation 2:     H2 (g) + ½ O2(g) → H2O (g)                        ∆Ho= -241.8 kJ
Equation 3:     B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)   ∆Ho= -2032.9 kJ

Which of the following statement/s is/are true in calculating the ∆Ho for the decomposition of B2H6 into its elements? Check all that apply.

   

Equation 1 was reversed and divided by 1/2.

   

Equation 2 was reversed and multiplied by 3.

   

Equation 1 was reveresed and divided by 2.

   

Equation 3 was neither reversed nor multiplied by a factor.

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