Given the following two half-reactions, determine which overall reaction is spontaneous and calculate the cell potential. Sn4*(aq) + 2 e ® Sn2*(aq) AI3+(aq) + 3 e¯ ® Al(s) E° = +0.15 V E° = -1.66 V a. 3 Sn 2*(aq) + 2 Al(s) ® 3 Sn 4+(aq) + 2 Al 3+(aq) E cell = +3.77 V b.3 Sn 4+(aq) + 2 Al(s) ® 3 Sn 2*(aq) + 2 Al 3+(aq) E cell = +1.81 V O C. 3 Sn 2+(ag) + 2 Al 3+(aq) ® 3 Sn 4*(aq) + 2 Al(s) E cell = -3.77 V ) d. 3 Sn 2*(aq) + 2 Al 3+ (aq) ® 3 Sn 4*(aq) + 2 Al(s) E cell = +1.81 V e. 3 Sn 4+(aq) + 2 Al(s) ® 3 Sn 2*(aq) + 2 Al (aq) 3+ E cell = +3.77 V

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Chapter8: Electrochemistry And Ionic Solutions
Section: Chapter Questions
Problem 8.10E: For each of the following reactions, determine the overall balanced electrochemical reaction, its...
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Given the following two half-reactions, determine which overall reaction is spontaneous and calculate the cell potential.
Sn4+,
(aq) + 2 e ® Sn2+(aq)
E° = +0.15 V
AЗt(ag) + 3 е @ Al(s)
E° = -1.66 V
a. 3 Sn
2*(aq) + 2 Al(s) ® 3 Sn 4+(aq) + 2 Al 3+(aq)
E cell = +3.77 V
O b.3 Sn 4*(aq) + 2 Al(s) ® 3 Sn 2+(aq) + 2 Al 3+(aq)
E cell = +1.81 V
O C. 3 Sn 2+(ag) + 2 Al (aq) ® 3 Sn 4*(aq) + 2 Al(s)
3+
E cell = -3.77 V
O d.3 Sn 2+(ag) + 2 Al
3+
(aq) ® 3 Sn
4+(aq) + 2 Al(s)
E cell = +1.81 V
e. 3 Sn 4*(aq) + 2 Al(s) ® 3 Sn 2*(aq) + 2 Al 3+(aq)
E cell = +3.77 V
Transcribed Image Text:Given the following two half-reactions, determine which overall reaction is spontaneous and calculate the cell potential. Sn4+, (aq) + 2 e ® Sn2+(aq) E° = +0.15 V AЗt(ag) + 3 е @ Al(s) E° = -1.66 V a. 3 Sn 2*(aq) + 2 Al(s) ® 3 Sn 4+(aq) + 2 Al 3+(aq) E cell = +3.77 V O b.3 Sn 4*(aq) + 2 Al(s) ® 3 Sn 2+(aq) + 2 Al 3+(aq) E cell = +1.81 V O C. 3 Sn 2+(ag) + 2 Al (aq) ® 3 Sn 4*(aq) + 2 Al(s) 3+ E cell = -3.77 V O d.3 Sn 2+(ag) + 2 Al 3+ (aq) ® 3 Sn 4+(aq) + 2 Al(s) E cell = +1.81 V e. 3 Sn 4*(aq) + 2 Al(s) ® 3 Sn 2*(aq) + 2 Al 3+(aq) E cell = +3.77 V
Use the standard reduction potentials below to determine which compound or ion is the best oxidizing agent?
Cl2(g) + 2 e ® 2 CI (aq)
E° = +1.36 V
Ag*(aq) + e ®Ag(s)
Fe2+(ag) + 2 e ® Fe(s)
E° = +0.80 V
E° = -0.44 V
-
2+
а. Fe
b. CI-
O c. Ag
d. Cl2
е. Fe
Transcribed Image Text:Use the standard reduction potentials below to determine which compound or ion is the best oxidizing agent? Cl2(g) + 2 e ® 2 CI (aq) E° = +1.36 V Ag*(aq) + e ®Ag(s) Fe2+(ag) + 2 e ® Fe(s) E° = +0.80 V E° = -0.44 V - 2+ а. Fe b. CI- O c. Ag d. Cl2 е. Fe
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