Given the reaction below, when 23.70 moles manganese acetate and 8.850 moles bromine, and 7.920 moles are permitted to react, how many moles hydrobromic acid form? (Next several questions use this same reaction). 2 Mn(CH3CO2)2 (aq) + 5 Br2 (1) + 8 H20 (1) → 2 HMNO4 (aq) + 10 HBr (aq) + 4 CH3CO2H (aq) Select one: a. 23.70 mol b. 8.850 mol C. 73.05 mol d. 84.70 mol e. 4.740 mol f. 146.1 mol g. 48.70 mol h. 7.920 mol i. 9.900 mol j. 17.70 mol k. none of these 1. 118.5 mol

Given the reaction below, when 23.70 moles manganese acetate and 8.850 moles bromine, and 7.920 moles are permitted to react, how many moles hydrobromic acid form? (Next several questions use this same reaction). 2 Mn(CH3CO2)2 (aq) + 5 Br2 (1) + 8 H20 (1) → 2 HMNO4 (aq) + 10 HBr (aq) + 4 CH3CO2H (aq) Select one: a. 23.70 mol b. 8.850 mol C. 73.05 mol d. 84.70 mol e. 4.740 mol f. 146.1 mol g. 48.70 mol h. 7.920 mol i. 9.900 mol j. 17.70 mol k. none of these 1. 118.5 mol

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter19: The Chemistry Of The Main-group Elements

Section: Chapter Questions

Problem 77QRT

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