[H+] [OH-] pH Acid, Base, Neutral [OH] = (1 x 10 -14):1 x 10- %3D pH = (-)log(10^-5) 1 x 10-5 10^-14:(10^-5) [H+] = (1 x 10 -14): (4.5 x 10-3 ) 4.5 x 10-3 [H+] = 2nd log (-)8.7 %3D 8.7 neutral

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter14: Acid-base Equilibria
Section: Chapter Questions
Problem 7E: What is the conjugate acid of each of the following? What is the conjugate base of each?. (a) OH-....
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[H+]
[OH-]
pH
Acid, Base, Neutral
[OH] = (1 x 10 -14):1 x 10-
%3D
pH = (-)log(10^-5)
1 x 10-5
10^-14:(10^-5)
[H+] = (1 x 10 -14): (4.5 x 10-3 )
4.5 x 10-3
[H+] = 2nd log (-)8.7
%3D
8.7
neutral
Transcribed Image Text:[H+] [OH-] pH Acid, Base, Neutral [OH] = (1 x 10 -14):1 x 10- %3D pH = (-)log(10^-5) 1 x 10-5 10^-14:(10^-5) [H+] = (1 x 10 -14): (4.5 x 10-3 ) 4.5 x 10-3 [H+] = 2nd log (-)8.7 %3D 8.7 neutral
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