he equilibrium constant Kc for the reaction fructose-1,6-diphosphate ⇋ glyceraldehyde-3-phosphate + dihydroxyacetone phosphate is 8.9 x 10-5 M at 250C and the behavior is assumed to be ideal?
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The equilibrium constant Kc for the reaction
fructose-1,6-diphosphate ⇋ glyceraldehyde-3-phosphate + dihydroxyacetone phosphate
is 8.9 x 10-5 M at 250C and the behavior is assumed to be ideal?
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- Calculate the equilibrium constant at 37oC for the reactionGlucose + 6O2 + 36ADP + 36Phospate → 6CO2+ 42H2O +36ATP ... ... ...Gibbs free energychange of Go= − 423 kcal/mole of GlucoseCalculate the equilibrium constant at 37oC for the reactionGlucose + 6O2 + 36ADP + 36Phospate → 6CO2+ 42H2O +36ATP ... ... ...Entropy change of Go= − 423 kcal/mole of GlucoseConcentration of ATP: 5.0*10-3 Concentration of ADP: 5.0*10-4 Concentration of Phosphate (Pi): 1.0*10-3 ∆G ̊= -31 kJ/mol at 298 K for the hydrolysis of ATP. Calculate the Q and ∆G for ATP hydrolysis.
- One step in glycolysis is the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate. The direct reaction of fructose-6-phosphate with inorganic phosphate fructose-6-phosphate + Pi ⇌ fructose-1,6-bisphosphate + H₂O is very unfavorable, with ∆G'°= 16.3 kJ/mol and K'eq = 1.39×10⁻³. However, in glycolysis the reaction is coupled to ATP hydrolysis: fructose-6-phosphate + ATP ⇌ fructose-1,6-phosphate + ADP and the reaction if favorable. What is the equilibrium [fructose-1,6-bisphosphate]/[fructose-6-phosphate] ratio in the coupled reaction when [ATP] = [ADP]? For ATP hydrolysis ∆G'°= -30.5 kJ/mol at 25°C.For the triose phosphate catalyzed reaction: dihydroxyacetone phosphate <--> glyceraldehyde-3-phosphate the standard change in Gibbs free energy is ΔG'º=7.53 kJ/mol. Calculate the ΔG for this reaction at 298K when the concentration of dihydroxyacetone phosphate is 0.161 M and the concentration of glyceraldehyde-3-phosphate is 0.00163 M.The equilibrium constant for the reaction below is 0.02 mol dm-3 at 298.000 K.Fructose 1,6-diphosphate _ glyceraldehyde 3-phosphate + dihydroxyacetone phosphateCalculate ΔG°.Provide answer to two decimal places and as J mol-1.
- The equilibrium constant, Keq, for the isomerization of dihydroxyacetone phosphate (DHAP) to glyceraldehyde 3-phosphate (GAP) is 0.0475 under standard conditions (298 K, 1 atm, pH 7). Calculate ∆G ̊’ for the reaction. What is ∆G’ for the isomerization reaction when the initial concentrations of DHAP and GAP are 2.2 ́ 10-4 M and 2.9 ́ 10-6 M, respectively? Assume a temperature of 298 K. The same enzyme catalyzes the reverse reaction, the isomerization of GAP to form DHAP. Assume the concentration of GAP remains constant at 2.9 ́ 10-6 M. What is the maximum concentration of DHAP that allows the reaction to proceed spontaneously in this direction?1.) Calculate ΔG'° for a reaction proceeding under biochemical standard conditions with a K'eq of 2.32. Give your answer in units of kJ/mol, but do not include the units as part of your answer (give the number only) 2.) What is the ΔG in kJ/mol for the reaction characterized in the previous question if the temperature is increased to 30°C and Q = 3.1? Again, please only give the numerical answer, do not include units.The value of ΔG° for the phosphorylation of glucose in glycolysis is 13.8 kJ/mol. What is the value of the equilibrium constant for the reaction at 25.0°C?
- The standard free energy variation, at 25 ºC, for equilibrium: Glucose-6-phosphate (G-6-P) Glucose-1-phosphate (G-1-P) is ΔGº '= + 7280 J / mol. Calculate a) The equilibrium constant of the reaction. b) The real change in free energy when one mole of G-6-P is transformed into G-1-P, both concentrations remaining constant and equal to 10mM and 2 mM respectively.Plants synthesize carbohydrates from CO2 and H2O by the process of photosynthesis. For example, 6CO2(g)+6H2O(l)C6H12O6(aq)+6O2(g) G=2.87103 kJ at pH 7.0 and 25°C. What is K for the reaction at 25°C?Calculate ΔG'° for a reaction proceeding under biochemical standard conditions with a K'eq of 2.32. Give your answer in units of kJ/mol, but do not include the units as part of your answer (give the number only)