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he working fluid is water. There is no heat transfer to or from the water, and the f the water per unit mass is constant. The water may be considered incompressibl a) Taking all the water in the reservoir, line, and hydraulic cylinder as the system he closed-system approach), calculate the work necessary to raise the rack and ca he change in potential energy of the water in the system). b) Repeat part (a), taking all the water plus the car and the rack as the system. c) Repeat part (a), taking an open-system approach; choose as your system the vo

he working fluid is water. There is no heat transfer to or from the water, and the f the water per unit mass is constant. The water may be considered incompressibl a) Taking all the water in the reservoir, line, and hydraulic cylinder as the system he closed-system approach), calculate the work necessary to raise the rack and ca he change in potential energy of the water in the system). b) Repeat part (a), taking all the water plus the car and the rack as the system. c) Repeat part (a), taking an open-system approach; choose as your system the vo

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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3. A hydraulic lift is shown below. The combined mass of the piston, rack, and car is 4000 lbm. The working fluid is water. There is no heat transfer to or from the water, and the internal energy of the water per unit mass is constant. The water may be considered incompressible. (a) Taking all the water in the reservoir, line, and hydraulic cylinder as the system (i.e., taking the closed-system approach), calculate the work necessary to raise the rack and car 1 ft (neglect the change in potential energy of the water in the system). (b) Repeat part (a), taking all the water plus the car and the rack as the system. (c) Repeat part (a), taking an open-system approach; choose as your system the volume of the hydraulic cylinder, excluding the piston, rack, and car. If the absolute pressure in the system is 1000 lbf/in², calculate the volume that must flow in to raise the car 1 ft. Reservoir Pump Hydraulic cylinder
Transcribed Image Text:3. A hydraulic lift is shown below. The combined mass of the piston, rack, and car is 4000 lbm. The working fluid is water. There is no heat transfer to or from the water, and the internal energy of the water per unit mass is constant. The water may be considered incompressible. (a) Taking all the water in the reservoir, line, and hydraulic cylinder as the system (i.e., taking the closed-system approach), calculate the work necessary to raise the rack and car 1 ft (neglect the change in potential energy of the water in the system). (b) Repeat part (a), taking all the water plus the car and the rack as the system. (c) Repeat part (a), taking an open-system approach; choose as your system the volume of the hydraulic cylinder, excluding the piston, rack, and car. If the absolute pressure in the system is 1000 lbf/in², calculate the volume that must flow in to raise the car 1 ft. Reservoir Pump Hydraulic cylinder
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i think your part B in this solution is for part A, how do you solve for part B now that we have to take water into account 

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I am confused on the (-) & how u went from ft/in^2 to m^3

dw energyflow vindmin dWenergyflow Vindmin (Pabs-Patm) Substituting values given as - ( Pvin)dmin dWenergyflow -P -4000 vindmin = (1000-14.7) vindmin=-4.06 ft- in² vindmin = 7.93 x 10-4 m³
Transcribed Image Text:dw energyflow vindmin dWenergyflow Vindmin (Pabs-Patm) Substituting values given as - ( Pvin)dmin dWenergyflow -P -4000 vindmin = (1000-14.7) vindmin=-4.06 ft- in² vindmin = 7.93 x 10-4 m³
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