Hemophilia and colorblindness are both recessive conditions caused by mutations in genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with the normal alleles and one chromosome with two mutant alleles), and the daughter’s sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has colorblindness only, and one has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness? Show your analysis

Hemophilia and colorblindness are both recessive conditions caused by mutations in genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with the normal alleles and one chromosome with two mutant alleles), and the daughter’s sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has colorblindness only, and one has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness? Show your analysis

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Description: Hemophilia and colorblindness are both recessive conditions caused by mutations in genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hem

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 2QP: Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To...

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Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome . To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness , their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters’ sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia 24 have neither of the traits , 1 has color blindness only and 1 has hemophilia only . how many centimorgans seperate the hemophilia locus from the locus of the color blindness.
The pedigree below shows the inheritance of the rare blistering disease (epidermolysis) in dogs. Affected individuals are indicated in black, and those not showing symptoms (phenotypically normal) of the disease in white. The pedigree below represents an autosomal recessive disease. What characteristic(s) of the pedigree supports this statement? Number the generations and individuals in this pedigree. Write the genotypes and their genotype probabilities for all the individuals in the pedigree. Use E/eas the allele symbols.
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You are a gene hunter, trying to find the genetic basis for a rare inherited disease. Examination of six pedigrees of families affected by the disease provides inconsistent results. For two of the families, the disease is co-inherited with markers on chromosome 7. For the other four families, the disease is co-inherited with markers on chromosome 12. Explain how this difference might have arisen.
In a population of martians the hair color (H= purple or h=green) and eye-color (E=red or e=yellow) are very close together on the same chromosome. One heterozygote male, who knows that his dad was homozygous dominant and his mom had green hair and yellow eyes is considering fertilizing a homozygous recessive female. How many green-haired yellow-eyed offspring (out of 16) would they expect to have?
Tay-Sachs disease is a rare human disease in which toxic substances accumulate in nerve cells. The recessive allele responsible for the disease is inherited in a simple Mendelian manner. For unknown reasons, the allele is more common in populations of Ashkenazi Jews of eastern Europe. A woman is planning to marry her first cousin, but the couple discovers that their shared grandfather’s sister died in infancy of Tay-Sachs disease.a. Draw the relevant parts of the pedigree, and show all the genotypes as completely as possible. b. What is the probability that the cousins’ first child will have Tay-Sachs disease, assuming that all people who marry into the family are homozygous normal?
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The most common form of colorblindness is a recessive, sex-linked hereditary con dition caused by a defect on the X chromosome. Females are XX, while males are XY. Individuals inherit one chromosome from each parent, with equal probability; for example, an individual has a 50% chance of inheriting their father's X chromosome, and a 50% chance of inheriting their father's Y chromosome. If a male has an X chromosome with the defect, he is colorblind. However, a female with only one defective X chromo some will not be colorblind. Thus, colorblindness is more common in males than females; 7% of males are colorblind but only 0.5% of females are colorblind. (a) Assume that the X chromosome with the wild-type allele is X+ and the one with the disease allele is X. What is the expected frequency of each possible female genotype: X+X+, X+X¯, and X-X-? What is the expected frequency of each possible male genotype: X+ Y and X-Y? (b) Suppose that two parents are not colorblind. What is the…
Figure 5.1 presented abbreviated pedigrees looking at the inheritance of X-linked human conditions. El Figure 5.1a initiated with a male who was color blind and had hemophilia A. The grandsons and great-grandsons of this male were either color blind and had hemophilia A, or they had neither condition. a. Which if any individuals in the G Fig. 5.1a pedigree is a double heterozygote? b. Are any of the grandsons or great-grandsons shown in the pedigree the product of recombinant type gametes? c. Do the genes responsible for color blindness and hemophilia A segregate independently? d. If you examined many pedigrees, each starting with a man who was simultaneously color blind and had hemophilia A, do you think any grandsons or great-grandsons would ever have one condition but not the other? L Figure 5.1b initiated with a male who was color blind and had hemophilia B. The grandsons of this male were either only color blind, only had hemophilia B, had both conditions, or they had neither…