Here are some data I found on the enzyme activity of mannose-6-phosphate isomerase (MPI) and MPI genotypes in the amphipod crustacean Platorchestia platensis. Because I didn't know whether sex also affected MPI activity, I separated the amphipods by sex. F and S stand for fast and slow respectively, and have to do with electrophoretic mobility on an agarose gel. FF, FS, and SS then reflect genotypes with FS being the heterozygote. Consider the numbers to be activity units. Analysis these data with the appropriate two-way ANOVA and state your conclusions below. Genotype Female Male FF 2.838 1.884 4.216 2.283 2.889 4.939 4.198 3.486 FS 3.55 2.396 4.556 2.956 3.087 3.105 1.943 2.649 SS 3.62 2.801 3.079 3.421 3.586 4.275 2.669 3.11
Here are some data I found on the enzyme activity of mannose-6-phosphate isomerase (MPI) and MPI genotypes in the amphipod crustacean Platorchestia platensis. Because I didn't know whether sex also affected MPI activity, I separated the amphipods by sex. F and S stand for fast and slow respectively, and have to do with electrophoretic mobility on an agarose gel. FF, FS, and SS then reflect genotypes with FS being the heterozygote. Consider the numbers to be activity units. Analysis these data with the appropriate two-way ANOVA and state your conclusions below. Genotype Female Male FF 2.838 1.884 4.216 2.283 2.889 4.939 4.198 3.486 FS 3.55 2.396 4.556 2.956 3.087 3.105 1.943 2.649 SS 3.62 2.801 3.079 3.421 3.586 4.275 2.669 3.11
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 2EQ: 2. Suppose that in Example 2.27, 400 units of food A, 500 units of B, and 600 units of C are placed...
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Here are some data I found on the enzyme activity of mannose-6-phosphate isomerase (MPI) and MPI genotypes in the amphipod crustacean Platorchestia platensis. Because I didn't know whether sex also affected MPI activity, I separated the amphipods by sex. F and S stand for fast and slow respectively, and have to do with electrophoretic mobility on an agarose gel. FF, FS, and SS then reflect genotypes with FS being the heterozygote. Consider the numbers to be activity units. Analysis these data with the appropriate two-way ANOVA and state your conclusions below.
| Genotype | Female | Male | |
| FF | 2.838 | 1.884 | |
| 4.216 | 2.283 | ||
| 2.889 | 4.939 | ||
| 4.198 | 3.486 | ||
| FS | 3.55 | 2.396 | |
| 4.556 | 2.956 | ||
| 3.087 | 3.105 | ||
| 1.943 | 2.649 | ||
| SS | 3.62 | 2.801 | |
| 3.079 | 3.421 | ||
| 3.586 | 4.275 | ||
| 2.669 | 3.11 |
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