. The container in Fig. 4.19 is initially evacuated. Then the valve is opened, and atmospheric air flows in, compressing the spring. The entire inflow and compres- sion process is adiabatic. The temperature of the atmospheric air is 20°C. When the process is over, the volume of the contained air is 10 m³, its pressure is 1 atm, and the work done on the piston and spring system is 13 kJ. The air in the container is perfectly mixed. What is the temperature of the air in the container?

Elements Of Electromagnetics
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4.37. The container in Fig. 4.19 is initially evacuated. Then the valve is opened, and
atmospheric air flows in, compressing the spring. The entire inflow and compres-
sion process is adiabatic. The temperature of the atmospheric air is 20°C. When
the process is over, the volume of the contained air is 10 m³, its pressure is 1 atm,
and the work done on the piston and spring system is 13 kJ. The air in the
container is perfectly mixed. What is the temperature of the air in the container?
Transcribed Image Text:4.37. The container in Fig. 4.19 is initially evacuated. Then the valve is opened, and atmospheric air flows in, compressing the spring. The entire inflow and compres- sion process is adiabatic. The temperature of the atmospheric air is 20°C. When the process is over, the volume of the contained air is 10 m³, its pressure is 1 atm, and the work done on the piston and spring system is 13 kJ. The air in the container is perfectly mixed. What is the temperature of the air in the container?
Valve
Spring
Piston ooooooo
FIGURE 4.19
Transcribed Image Text:Valve Spring Piston ooooooo FIGURE 4.19
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hi, where did u get this R value from. these are the values i have 

R= 8.314 J.mol-¹.K-¹ = 8.314 m³.Pa.mol-¹.K-1
= 83.14 cm³-bar-mol-1.K-1 = 8314 cm³-kPa-mol-1.K-1
= 82.06 cm³.(atm).mol-¹.K-¹ = 62,356 cm³ (torr).mol-¹.K-1
= 1.987 (cal)-mol-¹.K-¹ = 1.986 (Btu)(lb mole)-¹(R)-¹
= 0.7302 (ft)³(atm)(lb mol)¯¹(R)−¹ = 10.73 (ft)³(psia)(lb mol)-¹(R)—
= 1545 (ft)(lbf)(lb mol)-¹(R)-¹
=
Transcribed Image Text:R= 8.314 J.mol-¹.K-¹ = 8.314 m³.Pa.mol-¹.K-1 = 83.14 cm³-bar-mol-1.K-1 = 8314 cm³-kPa-mol-1.K-1 = 82.06 cm³.(atm).mol-¹.K-¹ = 62,356 cm³ (torr).mol-¹.K-1 = 1.987 (cal)-mol-¹.K-¹ = 1.986 (Btu)(lb mole)-¹(R)-¹ = 0.7302 (ft)³(atm)(lb mol)¯¹(R)−¹ = 10.73 (ft)³(psia)(lb mol)-¹(R)— = 1545 (ft)(lbf)(lb mol)-¹(R)-¹ =
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