HO ト=人 a) 1. Hz cgoi indlar catalyst OH Os ou, BuoH /H20 2. C+1-) b) 1. Osou, BUOH/HzO 2. Hz cgo, Lindlar catalyt c) I. Os Ou, BUOH /HzO Na css, NH3(8) -78°c 2. 1. Na c3), NH3ce,-78°c Os ou, BuOH /HzO 2.
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- Assume no acid-base catalysis occurs and the following data: Under biological conditions (310 K) 1. dGb = -20.00 kJ/mol. 2. The dG of E +S binding to ES (dGs) is -3.00 kJ/mol. 3. dGd mismatch of energy in ES = +2.00 kJ/mol. What is the catalytic power (kcat/k_uncat) at 360 K? Use 1 decimal place.Calculate ΔrG° for the following reaction at 387 K. HCN(g) + 2H2(g) → CH3NH2(g) ΔrH°= -158.0kJmol-1; ΔrS°= -219.9JK-1 mol-1Calculate the pK at 25 degrees C of the following reaction using the data in the table. Use R = 8.314 J/mol/K. 4A +2B → 1C + 3D + 4E ΔHf0(kJ/mol) S0(J/mol/K) A 18.05 19.84 B 3.31 12.02 C -13.73 18.57 D -9.71 10.09 E -8.96 19.45 Remember, pK = -log(K) Report the answer to two decimal points.
- CaCO3(s)<->Ca^2+(aq)+CO3^2-(g). write down Ksp for this reactionThe equilibrium constant for the reaction below is 0.02 mol dm-3 at 298.000 K.Fructose 1,6-diphosphate _ glyceraldehyde 3-phosphate + dihydroxyacetone phosphateCalculate ΔG°.Provide answer to two decimal places and as J mol-1.Provided the following information determine Δ?ΔHformation of C2H6(g). C(graphite) + O2(g) ⟶⟶ CO2(g) Δ?=−393.5??ΔH=−393.5kJ H2(g) + 1212O2(g) ⟶⟶ H2O(l) Δ?=−285.8??ΔH=−285.8kJ C2H6(g) + 7272O2(g) ⟶⟶ 2CO2(g) + 3H2O(l) Δ?=−1560.7??
- Pls pls pls help me solve the following question and make sure it's correct 10000% asap and explain, it's really important, pls and thanksGood explanation of this question Asap ThanksUse the following equilibria2CH4(g) <----> C2H6(g) + H2(g) Kc1 = 9.5 × 10-13CH4(g) + H2O(g) CH3OH(g) + H2(g) Kc2 = 2.8 × 10-21to calculate the value of Kc' for the following reaction:2CH3OH(g) + H2(g) <---> C2H6(g) + 2H2O(g) Enter your response in scientific notation, e.g. enter 2E3 for 2000