Can you please answer question 3.43 Integrative ActivitySimple Harmonic MotionThis small self-learning projectis a mandatory part of the course.Suppose we want to find a function y = f(t) such that its derivatives would satisfy the equationy"+o²y=0(DE)where a (a Greek lowercase letter called omega) is a positive constant. Such an equation involvinga function y = f(t) and its derivatives together is called a differential equation. Solving adifferential equation does not consist in finding a number that fits an equation, the goal is rather tofind a function that fits an equation. In the above, the goal is to find which function y = f(t)satisfies equation (DE).In general, finding functions that solve a differential equation is quite hard. We sometimes offera course on differential equations in your last term! For the specific differential equationy"+²y=0 that we have at hand, a solution is not too difficult. As you will verify below inquestion 3.41B, any function of the formy(t)= acos(at)+b sin(at)(GS1)where a and b are arbitrary constants, does satisfy differential equation (DE). Note thaty(t) = acos(at)+bsin(at) represents infinitely many possible functions due to the infinitelymany values that the arbitrary constants a and b can take. Moreover, it is shown in more advancedmathematics courses that there are no other possible functions satisfying equation (DE), that is,the infinitely many functions of equation (S1) give precisely all the possible functions that aresolutions of the differential equation (DE). We call (GS1) a general solution of (DE).With some trigonometry, it can be shown that another way to write the general solution of (DE) is(GS2)y(t) = Acos(at + p)where A and are constants and A is taken positive. As you will see in question 3.42 below, onemay switch between the two equivalent forms (GS1) and (GS2) of the general solution.There are many physical situations that lead to a differential equation such as (DE), called the(differential) equation of Simple Harmonic Motion; we will see one such example below. Asystem whose position as a function of time must satisfy the equation of Simple Harmonic Motion(DE), that is, whose position as a function of time will be given by a particular instance of equations(GS1) or (GS2), is said to undergo Simple Harmonic Motion. Note that in (GS2) corresponds toa "phase shift" (reason for the choice of the greak letter phi) compared to where the usual cosinefunction starts:dosePiftAmplitudeRTYTo aut Homework Question 3.41)A) Consider the differential equation y"+4n³y=0.Verify by direct substitution into its left hand side that the function y=3sin(2xt) is one of itspossible solutions.B) Similarly verify by direct substitution into the left hand side of (DE) that functions in (GS1)do form solutions of the differential equation (DE).C) Verify finally that functions in (GS2) similarly form solutions of (DE).Homework Question 3.42)The forms (GS1) and (GS2) of the general solution are actually equivalent. Indeed...A) i) Expand the cosine in (GS2) using a trigonometric identity: the addition formula for cosine.ii) Comparing your result in i) with equation (GS1): what are a and in terms of A and ?B) i) Considering your expressions just obtained for a and b, add a² and b², anduse this to write A in terms of a and b.ii) Divide the expression for b by that for a; express in terms of a and b.Now suppose that a particle rotates at constant speed along a circleof radius A, as shown beside.Let T denote the period of the motion (time required to completea circle) and let the initial angle at time t=0 be denoted by 0.Then the angle at any time t must be given by0(t) = 0 +27 +Therefore the x-coordinate of the particle isx(t) = Acos(0) = Acos(21+0),that is, the x-coordinate of the particle (or think of the point on thex-axis which is the shadow projection of the point on the circle)follows Simple Harmonic Motion with @= 2 and p=0.Acoso91A is called the amplitude of the motion, its frequency isf=+=% and is called the phase of the motion.Thus Simple Harmonic Motion can be seen as a component of circular motion! god aHomework Question 3.43)Suppose the equation of motion of a particle is governed by the following differential equation ofSimple Harmonic Motion:y"+36y=0.A) What are the frequency and the period of the motion?B) Write the general solution of the form (GS1) corresponding to this motion. (No work really...)C) If at time t=0 the particle has position y(0) = 4 and velocity y'(0) = 12, find the equationD) What is the amplitude of the motion?of motion of the particle, that is, find the position function y(t) of the particle at any time t.(Use the given initial conditions on position and velocity to find the appropriate a and b,conclude by writing down the resulting formula for y(t).)

Name: Can you please answer question 3.43 Integrative ActivitySimple Harmoni
Uploaded: 2024-03-20T06:58:04.000Z
Channel: Bartleby
Description: Can you please answer question 3.43 Integrative ActivitySimple Harmonic MotionThis small self-learning projectis a mandatory part of the course.Suppose we want to find a function y = f(t) such that its derivatives would satisfy the equationy"+o²y=0(D

Question

Can you please answer question 3.43 Integrative ActivitySimple Harmonic MotionThis small self-learning projectis a mandatory part of the course.Suppose we want to find a function y = f(t) such that its derivatives would satisfy the equationy&#34;+o²y=0(DE)where a (a Greek lowercase letter called omega) is a positive constant. Such an equation involvinga function y = f(t) and its derivatives together is called a differential equation. Solving adifferential equation does not consist in finding a number that fits an equation, the goal is rather tofind a function that fits an equation. In the above, the goal is to find which function y = f(t)satisfies equation (DE).In general, finding functions that solve a differential equation is quite hard. We sometimes offera course on differential equations in your last term! For the specific differential equationy&#34;+²y=0 that we have at hand, a solution is not too difficult. As you will verify below inquestion 3.41B, any function of the formy(t)= acos(at)+b sin(at)(GS1)where a and b are arbitrary constants, does satisfy differential equation (DE). Note thaty(t) = acos(at)+bsin(at) represents infinitely many possible functions due to the infinitelymany values that the arbitrary constants a and b can take. Moreover, it is shown in more advancedmathematics courses that there are no other possible functions satisfying equation (DE), that is,the infinitely many functions of equation (S1) give precisely all the possible functions that aresolutions of the differential equation (DE). We call (GS1) a general solution of (DE).With some trigonometry, it can be shown that another way to write the general solution of (DE) is(GS2)y(t) = Acos(at + p)where A and are constants and A is taken positive. As you will see in question 3.42 below, onemay switch between the two equivalent forms (GS1) and (GS2) of the general solution.There are many physical situations that lead to a differential equation such as (DE), called the(differential) equation of Simple Harmonic Motion; we will see one such example below. Asystem whose position as a function of time must satisfy the equation of Simple Harmonic Motion(DE), that is, whose position as a function of time will be given by a particular instance of equations(GS1) or (GS2), is said to undergo Simple Harmonic Motion. Note that in (GS2) corresponds toa &#34;phase shift&#34; (reason for the choice of the greak letter phi) compared to where the usual cosinefunction starts:dosePiftAmplitudeRTYTo aut Homework Question 3.41)A) Consider the differential equation y&#34;+4n³y=0.Verify by direct substitution into its left hand side that the function y=3sin(2xt) is one of itspossible solutions.B) Similarly verify by direct substitution into the left hand side of (DE) that functions in (GS1)do form solutions of the differential equation (DE).C) Verify finally that functions in (GS2) similarly form solutions of (DE).Homework Question 3.42)The forms (GS1) and (GS2) of the general solution are actually equivalent. Indeed...A) i) Expand the cosine in (GS2) using a trigonometric identity: the addition formula for cosine.ii) Comparing your result in i) with equation (GS1): what are a and in terms of A and ?B) i) Considering your expressions just obtained for a and b, add a² and b², anduse this to write A in terms of a and b.ii) Divide the expression for b by that for a; express in terms of a and b.Now suppose that a particle rotates at constant speed along a circleof radius A, as shown beside.Let T denote the period of the motion (time required to completea circle) and let the initial angle at time t=0 be denoted by 0.Then the angle at any time t must be given by0(t) = 0 +27 +Therefore the x-coordinate of the particle isx(t) = Acos(0) = Acos(21+0),that is, the x-coordinate of the particle (or think of the point on thex-axis which is the shadow projection of the point on the circle)follows Simple Harmonic Motion with @= 2 and p=0.Acoso91A is called the amplitude of the motion, its frequency isf=+=% and is called the phase of the motion.Thus Simple Harmonic Motion can be seen as a component of circular motion! god aHomework Question 3.43)Suppose the equation of motion of a particle is governed by the following differential equation ofSimple Harmonic Motion:y&#34;+36y=0.A) What are the frequency and the period of the motion?B) Write the general solution of the form (GS1) corresponding to this motion. (No work really...)C) If at time t=0 the particle has position y(0) = 4 and velocity y'(0) = 12, find the equationD) What is the amplitude of the motion?of motion of the particle, that is, find the position function y(t) of the particle at any time t.(Use the given initial conditions on position and velocity to find the appropriate a and b,conclude by writing down the resulting formula for y(t).)

Accepted Answer

Answered: Image /qna-images/answer/f48215de-605c-4481-8ab8-25dc8306f15c.jpg