How many moles of H2SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H2SO.(aq) → AL(SO.)3(aq) + 3 H2(g) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1 6.022 x 1023 2.02 g H2SO4 7.20 26.98 mol Al2(SO.)= 2 3 mol H2SO, 98.08 3.60 mol H2 342.14 10.8 g Al 21.6 2.40 mol Al

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter3: Mass Relations In Chemistry; Stoichiometry
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Problem 67QAP: When potassium chlorate is subjected to high temperatures, it decomposes into potassium chloride and...
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2:46 1
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Question 19 of 24
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How many moles of H2SO4 are required to
completely react with 7.20 mol of Al according
to the balanced chemical reaction:
2
Al(s) +
3
H¿SO.(aq) → Al2(SOa)3(aq) +
H2(g)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
1
6.022 x 1023
2.02
g H2SO4
7.20
26.98
mol Al2(SO.)=
2
3
mol H,SO4
98.08
3.60
mol H2
342.14
10.8
g Al
21.6
2.40
mol Al
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Transcribed Image Text:2:46 1 LTE Question 19 of 24 Submit How many moles of H2SO4 are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H¿SO.(aq) → Al2(SOa)3(aq) + H2(g) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1 6.022 x 1023 2.02 g H2SO4 7.20 26.98 mol Al2(SO.)= 2 3 mol H,SO4 98.08 3.60 mol H2 342.14 10.8 g Al 21.6 2.40 mol Al Tap here or pull up for additional resources
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