How many moles of natural gas (CH,) must burn to emit 273 kJ of heat? CH4(9) + 202(9) → CO2(9) + 2H20(g) A:H° = -802.3 kJ mo] 1 %3D

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.51QE: The enthalpy change when 1 mol methane (CH4) is burned is 890 kJ. It takes 44.0 kJ to vaporize 1 mol...
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Things haven't exactly been going Wile E. Coyote's way. For his latest scheme, he is going to set a fire in the Roadrunner's path and will try to torch the Roadrunner!
Part A
How many moles of natural gas (CH,) must burn to emit 273 kJ of heat?
CH4 (9) + 202(9) → CO2(9) + 2H20(9)
A:H° = -802.3 kJ mol-1
Express your answer using three significant figures.
?
mol
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Transcribed Image Text:Things haven't exactly been going Wile E. Coyote's way. For his latest scheme, he is going to set a fire in the Roadrunner's path and will try to torch the Roadrunner! Part A How many moles of natural gas (CH,) must burn to emit 273 kJ of heat? CH4 (9) + 202(9) → CO2(9) + 2H20(9) A:H° = -802.3 kJ mol-1 Express your answer using three significant figures. ? mol Submit Request Answer
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