How will I explain the cancellation of RPM here? 2. N=1 Srpmm-42,000kv= 250 kmW=180 kwP=1.313Solutionm² PAVangd= Ux40TINm2Finda) Vausb) nVarg = 42,000 kSh: Outputinput(250X)×40ITIS=Pock=ky(1.31 ) ( ) (88.42 m²190 kW* 42,000*(S.222'Sn = 31.46%.20160930= 88.42m= 5.22 ㎡m2180kW572.22 (0.3146%

round is not a unit .this is just a counting numbers like example - i move one point to second…

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How will I explain the cancellation of RPM here

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Question

How will I explain the cancellation of RPM here?

2. N=1 Srpm
m-42,000k
v= 250 km
W=180 kw
P=1.313
Solution
m² PAVang
d= Ux40
TIN
m
2
Find
a) Vaus
b) n
Varg = 42,000 k
S
h: Output
input
(250X)×40
ITIS
=
Pock
=
ky
(1.31 ) ( ) (88.42 m²
190 kW
* 42,000*(S.222
'S
n = 31.46%.
20160930
= 88.42m
= 5.22 ㎡
m
2
180kW
572.22 (
0.3146%

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