If 35.45 mL of 0.8121 M sodium carbonate solution reacts with excess lead (III) nitrate solution to form aqueous sodium nitrate and solid lead (III) carbonate, how many grams of lead (III) carbonate is formed?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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art 3 SHOW WORK
ond Shipp: Attempt 1
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Question 4 (0.5 points)
SHOW YOUR WORK.
G
**N*-*OO
If 35.45 mL of 0.8121 M sodium carbonate solution reacts with excess lead (III)
nitrate solution to form aqueous sodium nitrate and solid lead (III) carbonate, how
many grams of lead (III) carbonate is formed?
On your paper with your name and date:
1. Go from ionic compound name to formula (review Chp 5 as much as needed)
2. Balance the equation (review Chp 7 if needed).
3. Do the calculation showing ALL units, just like I did in solution stoichiometry
lecture.
a #
Transcribed Image Text:Ab GL B art 3 SHOW WORK ond Shipp: Attempt 1 Hu/d21/Ims/quizzing/user/attempt/quiz_start_frame_auto.d2l?ou=5956136&isprv=&drc=0&qi=5726766&cfql= Answer units ▷ Add attachments to support your work Question 4 (0.5 points) SHOW YOUR WORK. G **N*-*OO If 35.45 mL of 0.8121 M sodium carbonate solution reacts with excess lead (III) nitrate solution to form aqueous sodium nitrate and solid lead (III) carbonate, how many grams of lead (III) carbonate is formed? On your paper with your name and date: 1. Go from ionic compound name to formula (review Chp 5 as much as needed) 2. Balance the equation (review Chp 7 if needed). 3. Do the calculation showing ALL units, just like I did in solution stoichiometry lecture. a #
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