If 55.0 gg of molten iron(III) oxide reacts with 34.3 g of aluminum, what is the mass of iron produced? Fe2O3(l)+Al(l)⟶ΔFe(l)+Al2O3(s)Fe2O3(l)+Al(l)⟶ΔFe(l)+Al2O3(s) Express your answer with the appropriate units.
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If 55.0 gg of molten iron(III) oxide reacts with 34.3 g of aluminum, what is the mass of iron produced?
Fe2O3(l)+Al(l)⟶ΔFe(l)+Al2O3(s)Fe2O3(l)+Al(l)⟶ΔFe(l)+Al2O3(s)
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