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- . In Figure 6-11,a. in view of the position of HPA oxidase earlier in thepathway compared to that of HA oxidase, would youexpect people with tyrosinosis to show symptoms ofalkaptonuria?b. if a double mutant could be found, would you expecttyrosinosis to be epistatic to alkaptonuria?TPCK and TLCK are irreversible inhibitors of serine proteases. One ofthese inhibits trypsin and the other chymotrypsin. Which is which? Explainyour reasoning. Suggest the effects of each of the following mutations on the physiologicalrole of chymotrypsinogen:(a) R15S(b) C1S(c) T147SHow do you suppose the serine/threonine acetylase activity of YopJ might interfere with TAK1 activation?
- The intermediates A, B, C, D, E, and F all occur inthe same biochemical pathway. G is the product of thepathway, and mutants 1 through 7 are all G−, meaningthat they cannot produce substance G. The followingtable shows which intermediates will promote growthin each of the mutants. Arrange the intermediates inorder of their occurrence in the pathway, and indicatethe step in the pathway at which each mutant strain isblocked. A + in the table indicates that the strain willgrow if given that substance, an O means lack of growth.SupplementsMutant A B C D E F G1 + + + + + O +2 O O O O O O +3 O + + O + O +4 O + O O + O +5 + + + O + O +6 + + + + + + +7 O O O O + O +I have this strain of e coli. Is P+ o+ Z+ Y+ / I- P+ oC Z- Y+ Will beta-galactosidase and permease be expressed? If they are will they be inducible or constitutive?The ras protein is a mutated G protein that lacks GTPase activity. How does the absence of this activity affect the adenylyl cyclase pathway?
- TLCK and TPCK both use Histadine residues in the active site as inhibitors of serine proteases. Why is TLCK specific for trypsin and TPCK is specific for chymotrypsin?. An interesting mutation in lacI results in repressorswith 110-fold increased binding to both operator andnonoperator DNA. These repressors display a “reverse”induction curve, allowing β-galactosidase synthesis inthe absence of an inducer (IPTG) but partly repressingβ-galactosidase expression in the presence of IPTG. Howcan you explain this? (Note that, when IPTG binds a repressor, it does not completely destroy operator affinity,but rather it reduces affinity 110-fold. Additionally, ascells divide and new operators are generated by thesynthesis of daughter strands, the repressor must findthe new operators by searching along the DNA, rapidlybinding to nonoperator sequences and dissociating fromthem.)Which of the following dephosphorylates PI 3,4,5-trisphosphate, thereby blocking the activation of PKB/Akt?
- b. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Denote the point in the pathway in which each individual is blocked.a. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Draw the pathway leading to the production of protein E.CK1-41 is a non-competitive inhibitor of caspase-1. Explain.