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- Please write a full C++ code and provide code and output Two stacks of the same type are the same if they have the same number of elements and their elements at the corresponding positions are the same. Overload the relational operator == for the class linkedStackTypethat returns true if two stacks of the same type are the same; it returns false otherwise. Also, write the definition of the function template to overload this operator.Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function: void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support…Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function; void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support File…
- Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list def show_ids(M, level=0): k = M.first_node while k is not None: print(" "*2*level, id(k)) if (str(k.value.__class__.__name__) == str(M.__class__.__name__)): show_ids(k.value, level+1) k = k.next W=L2(Node(10, Node(L2(Node(14, Node(15, Node(L2(Node(16, Node(17))))))), Node(20, Node(30)))) )show_ids(W) Develop your solution as follows: - First copy the nodes of the current list (self) - Create a new list with the copied nodes - Loop through the nodes of the new list checking the value field - If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L):…Implement the function below void swap(int pos1, int pos2) {} Inital code to be completed: class LinkedList : public List { node* head; node* tail; int index; node* create_node(int num) { node* n = (node*) malloc(sizeof(node)); n->element = num; n->next = NULL; return n; } public: LinkedList() { index = 0; head = NULL; tail = NULL; } int add(int num) { addTail(num); return index; } int get(int pos) { node* currnode = head; int count =0; while (currnode != NULL){ count++; if (count == pos){ return currnode -> element; }else{ currnode = currnode -> next; } } return -1; } int size() { return index; } void swap(int pos1, int pos2) { } // WARNING!…There’s a somewhat imperfect analogy between a linked list and a railroad train, where individual cars represent links. Imagine how you would carry out various linked list operations, such as those implemented by the member functions insertFirst(), removeFirst(), and remove(int key) from the LinkList class in this hour. Also implement an insertAfter() function. You’ll need some sidings and switches. You can use a model train set if you have one. Otherwise, try drawing tracks on a piece of paper and using business cards for train cars.
- Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list Develop your solution as follows: First copy the nodes of the current list (self) Create a new list with the copied nodes Loop through the nodes of the new list checking the value field If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L): def clone(self): def clone_node(node): return <... YOUR CODE HERE ...> r = <... YOUR CODE HERE...> return r return L4_class(*args,**kwargs)I ASK THIS QUESTION HERE AND YOUR EXPERT SOLVE IT THIS WAY BUT CAN YOU WRITE THE main ( ) FOR THIS CODE Consider the following implementation of the node and doubly linked-list: template <class type>class node{public:type info;node<type> * next;// nextnode<type> * prev;//back }; template <class type>class doubly_linked_list{//data membersprivate:node<type> *head, *tail;int length;public:doubly_linked_list(){head = tail = NULL;length = 0;}bool isEmpty(){ // return (head==NULL);if (head == NULL)return true;elsereturn false;} void Append(type e){node<type> *newnode = new node<type>;newnode->info = e;if (isEmpty()){newnode->next = NULL;newnode->prev = NULL;head = newnode;tail = newnode;}else{tail->next = newnode;newnode->prev = tail;newnode->next = NULL;tail = newnode;}++length; } void Display(){if (isEmpty()) { cout << "The linked list is empty !!!!"; return; }cout << "list elements: ";node<type> *…You are going to implement a program that creates an unsorted list by using a linked list implemented by yourself. NOT allowed to use LinkedList class or any other classes that offers list functions. It is REQUIRED to use an ItemType class and a NodeType struct to solve this. Use C++, please read instructions carefully and new solution only! The “data.txt” file has three lines of data 100, 110, 120, 130, 140, 150, 160 100, 130, 160 1@0, 2@3, 3@END You need to 1. create an empty unsorted list 2. add the numbers from the first line to list using putItem() function. Then print all the current keys to command line in one line using printAll(). 3. delete the numbers given by the second line in the list by using deleteItem() function. Then print all the current keys to command line in one line using printAll().. 4. putItem () the numbers in the third line of the data file to the corresponding location in the list. For example, 1@0 means adding number 1 at position 0 of the list. Then…
- Add a new public member function to the LinkedList class named reverse() which reverses the items in the list. You must take advantage of the doubly-linked list structure to do this efficiently as discussed in the videos/pdfs, i.e. swap each node’s prev/next pointers, and finally swap headPtr/tailPtr. Demonstrate your function works by creating a sample list of a few entries in main(), printing out the contents of the list, reversing the list, and then printing out the contents of the list again to show that the list has been reversed. Note: your function must actually reverse the items in the doubly-linked list, not just print them out in reverse order! Note: we won't use the copy constructor in this assignment, and as such you aren't required to update the copy constructor to work with a doubly-linked list. This is what I have so far but its not working! template<class ItemType>void LinkedList<ItemType>::reverse(){ Node<ItemType>*curPtr,*prev,*next;…In C++, Write the implementation for the methods of the Node class including the constructor. The constructor should set value to the passed in parameter, and set the value of the next pointer to NULL. getNext() should return the value of the next pointer. setNext() should set the value of the next pointer to the parameter that is passed in. In the main() function below (where it says // Step 2 code here), write the code to make a list of 10 Node objects. To do this, make a root pointer which is a pointer to a Node object, and then use a loop to create new Nodes, hooking up the list using setNext() and getNext() for each node. Set the value of each new Node to be the even numbers 2 through 18 (in addition to the root node which has value 0). Make sure that your nodes are linked together! Write code to step through your linked list (where it says // Step 3 code here), printing the value of each node. Write code to clean up the list (where it says // Step 4 code here). Print a…This is in c++ Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. Don't print the dummy head node. Example input : 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 output: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData() method// to print the entire linked list //…