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- Implement the function f(w1, w2, w3) = w1w2w3 + w1w2 + w1w3 by using a 3 to 8 encoder and as few other gates as possible
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- Draw a 4-input adder for single-bit values: that is, a set of logic gates with 4 input wires each representing a number between 0 and 1 and a multi-bit output z, composed of wires z0 through z... (where z0 is the low-order bit, z1 the next, etc., up to the number of wires needed for this task). The gates should ensure that z = the sum of all four inputs.. Given the function: F(a, b, c) = (a + b)’c + a b c’ + a c a) Create the truth table for function F. 7b) Implement F by means of an 8-to-1 Multiplexer using block diagrams. Implement F by means of a 3-to-8 Decoder using block diagrams and any gates if needed.. Implement a circuit for the following problem using Logisim. The input to the circuit are 3 4-bit numbers, A,B,C. The sum of A and B is subtracted from C. The difference (result of subtraction) is compared with A. The circuit has 3 outputs lines depending on comparison. Use appropriate chips in Logisim for the operations mentioned Answer step by step
- Create a logic circuit using only basic gates such as AND, OR, NOR, NAND, NOT, etc. to implement a Subtractor that is capable of subtracting the second number from the first, by converting the second number into its 2's complement form and then adding the resulting number to the first number. You do not need to worry about accomodating the addition or subtraction of negative numbers. Also, create a limited ALU (Arithmetic logic unit) circuit using Logism that implements a Full Adder circuit capable of adding 2 – 4 bit binary numbers and subtracting 2- 4 bit binary numbers. Also, implement the ability to select a bitwise AND operation and a bitwise OR operation. For the ALU it is acceptable to use the Adder and Subtractor circuits that are listed under the "Arithmetic" folder in Logism. (Logism tips and tricks are useful here for multi-bit pins, and how to set up different gates to support more than 1 bit. If using YOUR adder or subtractor circuit in your ALU that is not only acceptable…Write a Verilog code for any one of the combinational arithmetic Circuits, which are having minimum of three variables using any type of Modeling.B) redraw the circuit from (a) using only NAND gates.
- Design a circuit that uses 4-bit full adders and AND gates. Given two 8-bit signed 2s-complement numbers A and B and a binary input signal M, your circuit should produce an 8-bit signed 2s-complement result R, as follows: if (M == 0) R = A; else R = A + B + 1;What is the smallest number of two-input NAND gates required to implement a circuit that takes a three-bit binary number as input and outputs the number times two?Use muxes to implement various gates. In each circuit, draw the specified number of 2:1 muxes and implement the given boolean expression. A mux input can be A, B, 0, 1, or the output of another device (e.g., another mux or a decoder). Be sure to label the S, 0, and 1 inputs of every mux. a. Use one 2:1 mux to implement NOT A (i.e. A') b. Use one 2:1 mux to implement A AND B (i.e. AB) c. Use one 2:1 mux to implement A OR B (i.e. A+B)
- Implement using Multiplexer 8:1 with residual variable. Please draw it using the logic gates, the circuit diagram. Do not draw the multiplexer chip per se. F=min(1,4,5,13,14,15)1a. Draw a circuit diagram using appropriate logic gates to implement a 3-bit comparator. Identifythe gates used in implementation and show its usage to compare two 3-bit words by writing thetruth table. b. Write the Boolean expression for the following 4 input circuit. Include sub-expressions foroutputs of each gate. c. Complete a truth table for the previous logic gate circuit in part b. d. Write the Boolean expression for the new circuit below. Then, simplify the following logic circuitusing the theorems in Boolean algebra. Show the steps clearly and specify the law used in eachstep. Finally draw the simplified circuit diagram.Plot the state transition diagram and write Verilog code with testbench simulation for 1 Design a sequence detector for the bit pattern “101010”