In a business, the Chief Executive Officer wants to know if his workers are for or against mandatory vaccinations. A random sample of 200 workers was taken and the results are shown in the MINITAB output below. Expected counts are printed below observed counts                   Managers           Team leaders                   Employees                    Total Approve     17                        22                                   15                   21.330                 17.820                            14.850                              54 Against      34                         25                                  14                    28.835                 24.090                            20.075                            73 No Opinion   28                     19                                   26                     28.835               24.090                            20.075                             73 Total             79                     66                                    55                                   200 Chi-sq = 0.878992 + 0.980494 + 0.001515 + 0.925168+ 0.034375 + 1.838387 + 0.02418 + 1.075471 + 1.74874 =7.507306 i. What is the value of the degree of freedom for this test?  ii. What is the p-value for this test?  iii. Carefully define the null and alternative hypotheses of the χ2 test underlying the generation of the above table.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 58E: What is meant by the sample space of an experiment?
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In a business, the Chief Executive Officer wants to know if his workers are for or against
mandatory vaccinations. A random sample of 200 workers was taken and the results are shown
in the MINITAB output below.


Expected counts are printed below observed counts


                  Managers           Team leaders                   Employees                    Total


Approve     17                        22                                   15
                  21.330                 17.820                            14.850                              54

Against      34                         25                                  14
                   28.835                 24.090                            20.075                            73

No Opinion   28                     19                                   26
                    28.835               24.090                            20.075                             73

Total             79                     66                                    55                                   200

Chi-sq = 0.878992 + 0.980494 + 0.001515 +
0.925168+ 0.034375 + 1.838387 +
0.02418 + 1.075471 + 1.74874 =7.507306


i. What is the value of the degree of freedom for this test? 
ii. What is the p-value for this test? 
iii. Carefully define the null and alternative hypotheses of the χ2
test underlying the generation of the above table. 
iv. Using α = 10%, what is the conclusion of this test? Give reasons for your answer

Hi

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