In a clinical trial of a drug intended to help people stop smoking,134subjects were treated with the drug for 13 weeks, and 12 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.16 as an alternative value of p, the power of the test is 0.96. Interpret this value of the power of the test.
In a clinical trial of a drug intended to help people stop smoking,134subjects were treated with the drug for 13 weeks, and 12 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.16 as an alternative value of p, the power of the test is 0.96. Interpret this value of the power of the test.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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In a clinical trial of a drug intended to help people stop smoking,134subjects were treated with the drug for 13 weeks, and 12 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.16 as an alternative value of p, the power of the test is 0.96. Interpret this value of the power of the test.
Transcribed Image Text:8.1.33
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In a clinical trial of a drug intended to help people stop smoking, 134 subjects were treated with the drug for 13 weeks, and 12 subjects experienced abdominal pain. If
someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance
level. Using 0.16 as an alternative value of p, the power of the test is 0.96. Interpret this value of the power of the test.
The power of 0.96 shows that there is a
% chance of rejecting the
V hypothesis of p =
when the true proportion is actually |. That is, if the
proportion of users who experience abdominal pain is actually , then there is a % chance of supporting the claim that the proportion of users who experience
abdominal pain is
V than 0.08.
Transcribed Image Text:The power of 0.96 shows that there is a
% chance of rejecting the
V hypothesis of p = when the true proportion is actually
. That is, if the
proportion of users who experience abdominal pain is actually , then there is a % chance of supporting the claim that the proportion of users who experience
abdominal pain is
V than 0.08.
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