One research study of illegal drug use among 12- to 17-year-olds reported a decrease in use (from 11.4% in 1997) to 9.8% now. Suppose a survey in a large high school reveals that, in a random sample of 1,056students, 96 report using illegal drugs. Use a 0.05 significance level to test the principal's claim that illegal drug use in her school is below the current national average.Formulate the null and alternative hypotheses. Choose the correct answer below.O A. Ho: p=0.098Ha: p>0.098О В. Но: р30.098H: p+0.098ОС. Но: р

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Asked Dec 14, 2019
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One research study of illegal drug use among 12- to 17-year-olds reported a decrease in use (from 11.4% in 1997) to 9.8% now. Suppose a survey in a large high school reveals that, in a random sample of 1,056
students, 96 report using illegal drugs. Use a 0.05 significance level to test the principal's claim that illegal drug use in her school is below the current national average.
Formulate the null and alternative hypotheses. Choose the correct answer below.
O A. Ho: p=0.098
Ha: p>0.098
О В. Но: р30.098
H: p+0.098
ОС. Но: р<0.098
Ha: p= 0.098
O D. Hn: p=0.098
H: p<0.098
Find the test statistic.
E(Round to two decimal places as needed.)
z=
Find the P-value for the found test statistic.
(Round to four decimal places as needed.)
P-value =
Now make a conclusion. Choose the correct answer below.
O A. Reject Ho. There is insufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average.
O B. Do not reject Hn. There is sufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average.
O C. Do not reject Hn. There is insufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average.
O D. Reject Hn. There is sufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average.
Click to select your answer(s).
Privacy - Terms
10:57 AM
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One research study of illegal drug use among 12- to 17-year-olds reported a decrease in use (from 11.4% in 1997) to 9.8% now. Suppose a survey in a large high school reveals that, in a random sample of 1,056 students, 96 report using illegal drugs. Use a 0.05 significance level to test the principal's claim that illegal drug use in her school is below the current national average. Formulate the null and alternative hypotheses. Choose the correct answer below. O A. Ho: p=0.098 Ha: p>0.098 О В. Но: р30.098 H: p+0.098 ОС. Но: р<0.098 Ha: p= 0.098 O D. Hn: p=0.098 H: p<0.098 Find the test statistic. E(Round to two decimal places as needed.) z= Find the P-value for the found test statistic. (Round to four decimal places as needed.) P-value = Now make a conclusion. Choose the correct answer below. O A. Reject Ho. There is insufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average. O B. Do not reject Hn. There is sufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average. O C. Do not reject Hn. There is insufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average. O D. Reject Hn. There is sufficient evidence to support the claim that illegal drug use in this principal's school is below the current national average. Click to select your answer(s). Privacy - Terms 10:57 AM

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Step 1

Given data

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96 n= 1056, x= 96, p =} 0.091 1056 p=0.098 ४|२

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Step 2

Formulation of Hypotheses:

The null hypothesis is proportion of illegal drug use is equal to the current national average.

Hp = 0.098

The alternative hypothesis is proportion of illegal drug use is below to the current national average

H1< 0.098

calculation of the test statistic

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calculation of the test statistic 0.091 – 0.098 -0.76509 z -0.77 0.098(1 – 0.098) 1056 p(1– p) п

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Step 3

calculation of p-value

p-value = 0.222109 ≈ 0.2221(From Excel =NORM.S. DIST(-0.76509,TRUE)

Conclusion

p-value > 0.05

Do not reject null hypothesis. There is insuff...

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