In a dissolution experiment of Nurofen 200mg/tablet and bupromax 400mg/tablet, 1 tablet each from the two brands i. e Nurofen 200mg and bupromax 400mg were placed in vessels containing 1 litter phosphate buffer, 5ml of the buffer aliquot was withdrawn from each of the vessels at 10 minutes and the UV absorbance of Nurofen 200mg was taken to be 0.234 and absorbance for bupromax was 0.456. A 300ppm of standard was prepared with aborbance of 1.866. What is the % dissolution of Nurofen 200mg and bupromax 400mg at 10minutes?

In a dissolution experiment of Nurofen 200mg/tablet and bupromax 400mg/tablet, 1 tablet each from the two brands i. e Nurofen 200mg and bupromax 400mg were placed in vessels containing 1 litter phosphate buffer, 5ml of the buffer aliquot was withdrawn from each of the vessels at 10 minutes and the UV absorbance of Nurofen 200mg was taken to be 0.234 and absorbance for bupromax was 0.456. A 300ppm of standard was prepared with aborbance of 1.866. What is the % dissolution of Nurofen 200mg and bupromax 400mg at 10minutes?

Macroscale and Microscale Organic Experiments

7th Edition

ISBN:9781305577190

Author:Kenneth L. Williamson, Katherine M. Masters

Publisher:Kenneth L. Williamson, Katherine M. Masters

Chapter8: Thin-layer Chromatography: Analyzing Analgesics And Isolating Lycopene From Tomato Paste

Section: Chapter Questions

Problem 10Q: A TLC plate showed two spots with Rf values of 0.25 and 0.26. The plate was removed from the...

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A TLC plate showed two spots with Rf values of 0.25 and 0.26. The plate was removed from the developing chamber, the residual solvent was allowed to evaporate from the plate, and then the plate was returned to the developing chamber. What would you expect to see after the second development was complete?
The buret was filled with 0.100 M HCl solution. Then was transferred in a 25.0 mL of saturated calcium hydroxide solution (2g of calcium hydroxide per 100 ml of water) in two separate E-flasks. Then 2 drops of phenolphthalein was added to each flask Titration data for the determination of the common ion effect: Trial 2: Final Buret reading (ml)-33.30; Initial Buret reading (ml)- 29.50; Temperature (Celcius)- 25 Voume of HCl used: Trial 2- 3.80mL. Report in proper sigfigs. 1. Compute for the moles of H+ used and the moles of OH- present. moles of H+ used = (concentration of HCl) × (volume of HCl used)moles of OH- = moles of H+ used 2. Use the dilution formula to determine the initial concentration of the common ion. C1V1 = C2V2 3. Construct an ICE table for the reaction.4. Calculate the molar solubility (in mol/L) of OH- and Ca2+.5. Determine the solubility of Ca(OH)2 in g/L. (MM of Ca(OH)2 = 74.096 g/mol).…
The buret was filled with 0.100 M HCl solution. Then was transferred in a 25.0 mL of saturated calcium hydroxide solution (2g of calcium hydroxide per 100 ml of water) in two separate E-flasks. Then 2 drops of phenolphthalein was added to each flask Titration data for the determination of the common ion effect: Trial 2: Final Buret reading (ml)-33.30; Initial Buret reading (ml)- 29.50; Temperature (Celcius)- 25 Voume of HCl used: Trial 2- 3.80mL. Report in proper sigfigs. 1. Calculate the molar solubility (in mol/L) of OH- and Ca2+.2. Determine the solubility of Ca(OH)2 in g/L. (MM of Ca(OH)2 = 74.096 g/mol). 3. Calculate the Ksp of Ca(OH)2. Make sure to include the effect of the common ion in the calculation.
The buret was filled with 0.100 M HCl solution. Then was transferred in a 25.0 mL of saturated calcium hydroxide solution (2g of calcium hydroxide per 100 ml of water) in two separate E-flasks. Then 2 drops of phenolphthalein was added to each flask Titration data for the determination of the common ion effect: Trial 1: Final Buret reading (ml)-29.50; Initial Buret reading (ml)- 26.10; Temperature (Celcius)- 25 Trial 2: Final Buret reading (ml)-33.30; Initial Buret reading (ml)- 29.50; Temperature (Celcius)- 25 Voume of HCl used: Trial 1- 3.40ml; Trial 2- 3.80mL. Report in proper sigfigs. 1. Compute for the moles of H+ used and the moles of OH- present. moles of H+ used = (concentration of HCl) × (volume of HCl used)moles of OH- = moles of H+ used 2. Use the dilution formula to determine the initial concentration of the common ion. C1V1 = C2V2 3. Construct an ICE table for the reaction.4. Calculate the molar solubility…
A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to pH 3 and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of 0.569 at 283.3 nm. Five-milliliter aliquots of standard solutions containing 0.400 and 0.600 ppm of lead were treated in the same way and yielded absorbances of 0.396 and 0.599. Please calculate the concentration of lead in the sample in ppm.
A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to pH 3 and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of 0.527 at 283.3 nm. Five-milliliter aliquots of standard solutions containing 0.400 and 0.600 ppm of lead were treated in the same way and yielded absorbances of 0.396 and 0.599. Find the concentration of lead in the sample in ppm assuming that Beer’s law is followed.
Calculate the [FeSCN2+] using volumes of stock solutions. Presume that all the SCN– ions react. STANDARD SAMPLE Volume of Fe(NO3)3 (mL) Volume of SCN- (mL) Volume of H2O (mL) [FeSCN2+] Absorbance 1 2.5 2.0 20.5 0.1918 2 2.5 1.5 21.0 0.3239 3 2.5 1.0 21.5 0.4965 4 2.5 0.5 22.0 0.6209 Stock [Fe(NO3)3] = 0.200 M, Stock [SCN-] = 0.0020 M Any help would be greatly appreciated Please and thanks :)
A 25.0 cm portion of 0.200, mol dm^-3 sodium ethanedioate solution was warmed and titrated against a solution of potassium manganate(VII). If 17.2 cm^3 of potassium manganate(VII) are required, what is its concentration?
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Compare and contrast the amount of caffeine obtained from the single vs multipleextractions with Red Bull and Coca-Cola beverages. Explain why this has occured. Single Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 5ml Red Bull 2.412 57.9mg/100ml 5ml Coca-Cola 0.716 16.2mg/100ml Multiple Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 10ml Red Bull 3.253 78.453mg/100ml 10ml Coca-Cola 0.785 17.844mg/100ml
How much benzoic acid, Ka = 6.3⋅10-5, will remain undissociated in the aqueous phase of a 50 % oil-water emulsion if the initial concentration of benzoic acid in the aqueous phase is 0.5 %? The aqueous phase is buffered at pH 5. The true oil/water partition coefficient (for undissociated benzoic acid) is equal to 5.33. Assume that benzoic acid remains as a monomer in the oil phase.
A juice concentrate was colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the sample solution and various concentrations of the standard glucose solution were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbances at 480 nm for distilled water, glucose standard, and for the sample are 0.052, 1.702, and 0.926, respectively. What is the reducing sugar concentration (mg/mL) in the juice concentrate? The equation of the line was plotted to be: y = 1.6656x - 0.0885 0.578 mg/mL 577.9 mg/mL 57.7 mg/mL 5.78 mg/mL