In a random sample of five people, the mean driving distance to work was 25.1 miles and the standard deviation was 6.6 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean p. Interpret the results. ..... Identify the margin of error. miles (Round to one decimal place as needed.)

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 90%…

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A: Given that Sample size n = 21 Sample SD = 8.5 The critical values of Chi-square at 90% confidence…

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A: Given information Hypothesized mean µ = 19 inches Sample size (n) = 49 Mean x̅  = 18.5 inches…

Q: For a confidence level of 80% with a sample size of 24, find the t-score.

A: From the provided information, Confidence level = 80% Level of significance (α) = 1 – 0.80 = 0.20…

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

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Q: For the provided sample​ mean, sample​ size, and population standard​ deviation, complete parts​ (a)…

A: Given data,n=100x=22σ=3z-value at 95% confidence is Zc=1.96

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A: From the provided information, Sample size (n) = 10 Sample mean (x̅) = 38 Sample standard deviation…

Q: Use the given confidence interval to find the margin of error and the sample mean . (12.9, 20.1)

A: See the handwritten solution

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Q: The average sa!lary of 64 employee was 5400 and the sample standard deviation was 260. Find the 95%…

A: Solution

Q: In the context of the previous question, construct a 95% confidence interval of the mean salary of…

A: Note- Here I giving a solution for the second photo.   Given information- Sample size, n = 40…

Q: Use the given confidence interval to find the margin of error and the sample mean.

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Q: Given a mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95 %…

A: A mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95% confidence…

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Q: The average salary of 64 employee was 5400 and the sample standard deviation was 270. Find the 90%…

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Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 95%…

A: It's a t distribution as the population standard deviation is unknown

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A: We have given that  Mean: 3.2 Standard deviation: 4 N: 160

Q: The following data shows the number of hours slept by a patient in 1 weeks 12 18 09 16 11 10 08 i.…

A: (i) The unbiased estimate for the population mean is,

Q: Given a mean of 62, a standard deviation of 8, and a sample size of 150, construct a 99.7%…

A: Given that a mean of 62, a standard deviation of 8 and a sample size of 150. We have to construct a…

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Q: A random sample of the number of farms (in thousands) in various states follows. Use these data to…

A: It is given that the population standard deviation is 31.

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A: According to the provided information, 10.18<μ<11.90

Q: According to NEA Advocate (2007), the averages for the 2005-2006 academic year, 34 CSU Stanislaus…

A: The provided information is x¯1=$65800x¯2=$72400σ1=$12000σ2=$8000n1=34n2=40α=0.05 The critical value…

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A: Number of samples (n) = 12 63 3969 64 4096 64 4096 56 3136 64 4096 53 2809 61…

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A: The sample mean is obtained below: Thus, the sample mean is 844.375.   The sample standard…

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A: Given: China n=50x¯=22.5s=9.75 America n=33x¯=33.15s=11.6

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Q: The average salary of 64 employee was 5400 and the sample standard deviation was 260. Find the 90 %…

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Q: The data below gives the mean price (in cents) of a litre of regular gasoline at self-service…

A: Given data of price/litre is105.4,109.2,98.8,94.9,109.7,112.5sample size(n)=6

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A: Solution

Q: (a) Does the size of the orifice affect the mean percentage of radon released? Use a =0.05. (b) Find…

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Q: In a recent study of 42 eighth graders, the mean number of hours per week that they watched…

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A: It is given that confidence level is 0.90, standard deviation is 100 and margin of error E is 11.

Q: In the construction of an 88% Confidence Interval for a population mean u, a has the value of

A: Incomplete

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A: Solution: Let X be the heart rate. From the given information, x-bar is 96 beats per minute, S=5 and…

Q: The average weight of 35 randomly selected compact automobiles was 2680 pounds. The sample standard…

A: From the provided information, Sample size (n) = 61 Sample mean (x̅) = 2680 Sample standard…