In a random sample of six people, the mean driving distance to work was 25.7 miles and the standard deviation was 6.7 miles. Assuming the population is normally distributed and using the t-distribution, a 99 % confidence interval for the population mean mu is left parenthesis 14.7 comma 36.7 right parenthesis (and the margin of error is 11.0 ). Through research, it has been found that the population standard deviation of driving distances to work is 5.5 . Using the standard normal distribution with the appropriate calculations for a standard deviation that is known, find the margin of error and construct a 99 % confidence interval for the population mean mu . Interpret and compare the results. Identify the margin of error. nothing ▼ square miles miles miles per hour (Round to one decimal place as needed.) Construct a 99 % confidence interval for the population mean. left parenthesis nothing comma nothing right parenthesis (Round to one decimal place as needed.) Interpret the results. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) A. nothing % of all random samples of six people from the population will have a mean driving distance to work (in miles) that is between the interval's endpoints. B. With nothing % confidence, it can be said that most driving distances to work (in miles) in the population are between the interval's endpoints. C. It can be said that nothing % of the population has a driving distance to work (in miles) that is between the interval's endpoints. D. With nothing % confidence, it can be said that the population mean driving distance to work (in miles) is between the interval's endpoints. Compare these results to the results that used the t-distribution. The new confidence interval is ▼ as wide as wider than narrower than the confidence interval that used the t-distribution and has ▼ a greater a lesser the same center.

In a random sample of six people, the mean driving distance to work was 25.7 miles and the standard deviation was 6.7 miles. Assuming the population is normally distributed and using the t-distribution, a 99 % confidence interval for the population mean mu is left parenthesis 14.7 comma 36.7 right parenthesis (and the margin of error is 11.0 ). Through research, it has been found that the population standard deviation of driving distances to work is 5.5 . Using the standard normal distribution with the appropriate calculations for a standard deviation that is known, find the margin of error and construct a 99 % confidence interval for the population mean mu . Interpret and compare the results. Identify the margin of error. nothing ▼ square miles miles miles per hour (Round to one decimal place as needed.) Construct a 99 % confidence interval for the population mean. left parenthesis nothing comma nothing right parenthesis (Round to one decimal place as needed.) Interpret the results. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) A. nothing % of all random samples of six people from the population will have a mean driving distance to work (in miles) that is between the interval's endpoints. B. With nothing % confidence, it can be said that most driving distances to work (in miles) in the population are between the interval's endpoints. C. It can be said that nothing % of the population has a driving distance to work (in miles) that is between the interval's endpoints. D. With nothing % confidence, it can be said that the population mean driving distance to work (in miles) is between the interval's endpoints. Compare these results to the results that used the t-distribution. The new confidence interval is ▼ as wide as wider than narrower than the confidence interval that used the t-distribution and has ▼ a greater a lesser the same center.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

In a random sample of

six

people, the mean driving distance to work was

25.7

miles and the standard deviation was

6.7

miles. Assuming the population is normally distributed and using the t-distribution, a

confidence interval for the population mean

left parenthesis 14.7 comma 36.7 right parenthesis

(and the margin of error is

11.0

Through research, it has been found that the population standard deviation of driving distances to work is

5.5

Using the standard normal distribution with the appropriate calculations for a standard deviation that is known, find the margin of error and construct a

confidence interval for the population mean

Interpret and compare the results.

Identify the margin of error.

nothing

▼

square miles

miles

miles per hour

(Round to one decimal place as needed.)

Construct a

confidence interval for the population mean.

left parenthesis nothing comma nothing right parenthesis

(Round to one decimal place as needed.)

Interpret the results. Select the correct choice below and fill in the answer box to complete your choice.

(Type an integer or a decimal. Do not round.)

nothing

of all random samples of

six

people from the population will have a mean driving distance to work (in miles) that is between the interval's endpoints.

With

nothing

confidence, it can be said that most driving distances to work (in miles) in the population are between the interval's endpoints.

It can be said that

nothing

of the population has a driving distance to work (in miles) that is between the interval's endpoints.

With

nothing

confidence, it can be said that the population mean driving distance to work (in miles) is between the interval's endpoints.

Compare these results to the results that used the t-distribution.

The new confidence interval is

▼

as wide as

wider than

narrower than

the confidence interval that used the t-distribution and has

▼

a greater

a lesser

the same

center.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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