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In a survey of 1136 people, 848 people said they voted in a recent presidential election. Voting records show that 72% of eligible voters actually did vote. Given that 72% of eligible voters actually did vote, (a) find the probability that among 1136 randomly selected voters, at least 848 actually did vote. (b) What do the results from part (a) suggest? (a) P(X 2 848) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? O A. People are being honest because the probability of P(x2848) is at least 1%. O B. Some people are being less than honest because P(xz848) is at least 1%. O C. Some people are being less than honest because P(x2848) is fess than 5%.

In a survey of 1136 people, 848 people said they voted in a recent presidential election. Voting records show that 72% of eligible voters actually did vote. Given that 72% of eligible voters actually did vote, (a) find the probability that among 1136 randomly selected voters, at least 848 actually did vote. (b) What do the results from part (a) suggest? (a) P(X 2 848) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? O A. People are being honest because the probability of P(x2848) is at least 1%. O B. Some people are being less than honest because P(xz848) is at least 1%. O C. Some people are being less than honest because P(x2848) is fess than 5%.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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In a survey of 1136 people, 848 people said they voted in a recent presidential election. Voting records show that 72% of eligible voters actually did vote. Given that 72% of eligible voters actually did vote, (a) find the probability that among 1136 randomly selected voters, at least 848 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2 848) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? O A. People are being honest because the probability of P(x2848) is at least 1%. O B. Some people are being less than honest because P(x2848) is at least 1%. O C. Some people are being less than honest because P(x2848) is less than 5%. O D. People are being honest because the probability of P(x2848) is less than 5%
Transcribed Image Text:In a survey of 1136 people, 848 people said they voted in a recent presidential election. Voting records show that 72% of eligible voters actually did vote. Given that 72% of eligible voters actually did vote, (a) find the probability that among 1136 randomly selected voters, at least 848 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2 848) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? O A. People are being honest because the probability of P(x2848) is at least 1%. O B. Some people are being less than honest because P(x2848) is at least 1%. O C. Some people are being less than honest because P(x2848) is less than 5%. O D. People are being honest because the probability of P(x2848) is less than 5%
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