To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected 200 people from San Diego and found that 101 were subscribed. Find a 95% confidence interval estimate for the true proportion of San Diegans subscribed to Disney+. Round to four decimal places.

Q: A wildlife refuge takes a survey of its past donors to try to estimate the percentage of all past…

A: We have given that,  Favorable cases (X) = 42 and sample size (n) = 150 Then,  We will find the 99%…

Q: In another pre-election poll, a pollster finds that 438 out of 600 people polled favor, Smith.…

A: Given, X = 438 N = 600 The sample proportion is given by:

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: A computer software magazine compares the rates of malware infection for computers protected by…

A: There are two independent samples which are software A and software B. Both samples are drawn from…

Q: When 460 junior college students were surveyed, 100 said they have a passport. Construct a 95%…

A: Given that there are 460 junior college students and 100 said they have a passport. That is, n=460…

Q: The figure to the right shows the results of a survoy in which 1013 adults from Country A, 1001…

A: It was found that out of the 1013 adults from country A, 33% of the adults say national identity is…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

Q: a recent survey at a small Midwestern college, 39 of 140 randomly selected students revealed that…

A: Here it is given that- total number of observations(n) = 140 Proportion (p) = 39140= 0.28 So, q =…

Q: A researcher surveys 50 individuals in Smithville and 40 in Amherst, finding that 30% of smithville…

A: Given: Smithville is taken as the first group. Amherst is taken as the second group.…

Q: A university dean is interested in determining the proportion of students who receive some financial…

A: The point estimate=p^=118200=0.59n=sample size= 200z=critical value of 95% confidence…

Q: In a random sample of 90 homeowners, 71% of them have received robocalls over an outstanding debt.…

A: Sample size(n)=90 Sample proportion who have received robocalls  over an outstanding…

Q: A random sample of 75 college students of MSU is selected and 16 are found to have motorcycles on…

A: From the given information, The sample size is 75. Out of 75 students, 16 are found to have…

Q: A survey of 1,898 adults with lawns conducted by a researcher found that 45% of the adults said that…

A: Obtain the 95% confidence interval of the true proportion who said that dandelions were the toughest…

Q: In an exit poll of 625 scientifically and randomly selected voters, 340 expressed support for…

A:

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A:

Q: An opinion poll asks an SRS of 100 college seniors how they view their job prospects. In all, 54 say…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval for…

Q: A farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to…

A: Given that, Sample size n=100 Sample proportion of booms that yield marketable strawberries…

Q: In a Harvard School of Public Health survey, 2105 of 10,904 randomly selected U.S. college students…

A: Given data is appropriate for testing of hypothesis. Because it is a large sample test for single…

Q: Of 400 randomly selected medical students, 21 said that they planned to work in a  rural community.…

A:

Q: airline has surveyed a simple random sample of air travelers to find out whether they would be…

A:

Q: A local health center noted that in a sample of 400 patients, 80 were referred to them by the local…

A: From the provided information, Sample size (n) = 400 From which 80 were referred to them by the…

Q: perimental treatments or medicines. The sample consisted of 1220 adult Internet users, and…

A: The value of z at 95% confidence level is 1.96, which can be found by using the standard normal…

Q: The Okeechobee County Economic Development Board needs to estimate the proportion of all county…

A: It is given that 10.5% of the county residents in each sample have earned at least a bachelor's…

Q: In a recent poll of 900 randomly selected adults, 37 % reported that they could not swim 24 yards…

A: Given information: In a poll of 900, randomly selected adults were examined if they could swim 24…

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected…

A: Given that, n=200 p^=101200=0.505

Q: must prove that it has more than 25% of the viewing audience after its initial 13-week run in order…

A: The value of z at 99% confidence level is 2.575, which can be found by using the standard normal…

Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…

A: We want to find 95% CI for population proportion (p)

Q: 2. In a survey of 1024 US adults, 287 said that their favorite sport to watch is football. a. Find a…

A: It is given that the survey contains 1024 US adults and the number of US adults who favorite sport…

Q: In a sample of 600 Ottawa families, it is found that 360 rent their dwellings while 240 own their…

A: It is given that sample size (n) is 360 and x is 240.

Q: In a survey of 2,472 adults, 1,949 reported that​ e-mails are easy to​ misinterpret, but only 1,281…

A: It is given that sample size (n) is 2472 and x is 1,949.

Q: wed that 122 involved uninsured drivers. Construct a 96% confidence interval for the proportion of…

A: A survey of 500 non-fatal accidents showed that 122 involved uninsured drivers. Let X be the number…

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: Construct a 95% confidence interval for the population proportion of students who graduate within…

A: The sample size is n = 400 And the number of students who graduate within six years, X = 108 The…

Q: The manager of a local fast-food restaurant is concerned about evil customers who ask for a free cup…

A:

Q: In a survey of 1024 US adults, 287 said that their favorite sport to watch is football. a. Find a…

A: From the provided information, Sample size (n) = 1024 Out of which 287 said that their favourite…

Q: n a recent Zogby International Poll, nine of 48 respondents rated the likelihood of a terrorist…

A: Given that : x = 9 n = 48

Q: In a recent poll, 150 people were asked if they liked olives, and 23% said they did. Find the margin…

A: Given: n=150 p=0.23 α=0.1

Q: Suppose that a safety group surveyed 1,200 drivers. Among those​ surveyed,78​% said that careless or…

A: Obtain the 99% confidence interval estimate for the true proportion in the population of all drivers…

Q: In a preelection poll, a pollster finds that 442 out of 650 people polled favor Smith. Construct the…

A: We need to construct the 95% confidence interval for the population proportion. We have given the…

Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: A local school board wants to determine the proportion of households in the district that would…

A:

Q: A recent Gallup poll asked a random sample of 1010 Americans to respond to the statement, "If the…

A: Given,95% confidence interval for the proportion who would respond "Strongly agree" or "Agree" is…

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected…

A: Given: p=population proportionp^=101200n=200α=0.05z=1.96

Q: A random sample of 180 men indicated that 50 were smokers, and a random sample of 150 women surveyed…

A: Given; p1=50180=0.28p2=39150=0.26Level of significance=0.02 Confidence interval is given by-…

Q: f a Random Sample of 450 adults includes 155 who identify as happy, compute an 80% confidence…

A: Given data,n=450x=155sample proportion p=xn=155450=0.34z-value at 80% confidence is Zc=1.282

Q: 2. A survey found that out of 900 workers, 150 said that they were interrupted by frank phone calls.…

A: In question, We have given the number of favorable cases 150 and sample size 900 then we'll find 95%…

Q: In a survey of 500 potential jurors, one study found that 350 were regular watchers of at least one…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.