In Kjeldahi analysis, a flour sample weighing 0.9857 was digested in concentrated H,So, for 45 min. a concentrated solution of NaOH was added such that all the nitrogen was converted to NH. Following this, the NH, wes distilled into a fiask containing 50.00 ml of 0.1011 N H,So, The excess required 5.12 ml of 0.1266 N NaOH for titration. What is the % Nand Séprotein in the sample?
In Kjeldahi analysis, a flour sample weighing 0.9857 was digested in concentrated H,So, for 45 min. a concentrated solution of NaOH was added such that all the nitrogen was converted to NH. Following this, the NH, wes distilled into a fiask containing 50.00 ml of 0.1011 N H,So, The excess required 5.12 ml of 0.1266 N NaOH for titration. What is the % Nand Séprotein in the sample?
Chapter3: Statistical Tests With Excel
Section: Chapter Questions
Problem 3P
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Show solution round off answer to four decimal places. Formula is given already
Answer:
% N =
% protein =
![N × V × mEq
sample weight(g)
% purity
sx wt (g)
х 100
N =
mEq x mL of solution
[(N x V)acid – (N × V) pase] × mEq
N = fM
% рurity :
-× 100
Sx wt (g)
(V blank – V sample) × N × mEq
sample weight (g)
% purity :
X 100](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F278e2758-8057-49d0-9d3f-a3ea5adaa302%2F82facbd5-611e-4fb1-8edf-b98d126926b7%2Fxzyp4q6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:N × V × mEq
sample weight(g)
% purity
sx wt (g)
х 100
N =
mEq x mL of solution
[(N x V)acid – (N × V) pase] × mEq
N = fM
% рurity :
-× 100
Sx wt (g)
(V blank – V sample) × N × mEq
sample weight (g)
% purity :
X 100
Transcribed Image Text:In Kjeldahl analysis, a flour sample weighing 0.9857 was digested in concentrated H;SO, for 45 min. a concentrated solution of
NaOH was added such that all the nitrogen was converted to NH3. Following this, the NH3 was distilled into a flask containing 50.00
mL of 0.1011 N H;SO. The excess required 5.12 ml of 0.1266 N NaOH for titration. What is the 9% Nand %protein in the sample?
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