In order to determine the cross section for neutron capture, you are irradiating a thin tin foil, in the form of a circular disk of diameter 2.8 mm and thickness 1.82 µm, with neutrons t produce the reaction n+120sn-121sn + y. By observing the outgoing gamma-ray photons in a detector, you determine that the tin decays at a rate of 2.88 x 103 per second. From an independent measurement, you have determined the neutron flux to be 5.00 x 1010 neutrons/cm2/s. What value do you deduce for the cross section for this reaction? (The density of tin is 7.31 g/cm³. Use values from this table.) b

Inquiry into Physics
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ISBN:9781337515863
Author:Ostdiek
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Chapter11: Nuclear Physics
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In order to determine the cross section for neutron capture, you are irradiating a thin tin foil, in the form of a circular disk of diameter 2.8 mm and thickness 1.82 μm, with neutrons to produce the reaction n + 120sn → 121sn + y. By observing the outgoing gamma-ray
photons in a detector, you determine that the tin decays at a rate of 2.88 x 103 per second. From an independent measurement, you have determined the neutron flux to be 5.00 x 1010 neutrons/cm²/s. What value do you deduce for the cross section for this reaction?
(The density of tin is 7.31 g/cm³. Use values from this table.)
b
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Transcribed Image Text:1. DETAILS eBook MY NOTES ASK YOUR TEACHER In order to determine the cross section for neutron capture, you are irradiating a thin tin foil, in the form of a circular disk of diameter 2.8 mm and thickness 1.82 μm, with neutrons to produce the reaction n + 120sn → 121sn + y. By observing the outgoing gamma-ray photons in a detector, you determine that the tin decays at a rate of 2.88 x 103 per second. From an independent measurement, you have determined the neutron flux to be 5.00 x 1010 neutrons/cm²/s. What value do you deduce for the cross section for this reaction? (The density of tin is 7.31 g/cm³. Use values from this table.) b Additional Materials
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