In testing a hypothesis Ho: u > 3, we found that the test statistic is t = 2.7565, the critical value is t = 2.064 The decision would be to: a. for 2.7565 Fail to accept the null hypothesis b. for 2.7565 accept the alternative hypothesis O c. for 2.7565 Reject the alternative hypothesis d. for 2.7565 Reject the null hypothesis

In testing a hypothesis Ho: u > 3, we found that the test statistic is t = 2.7565, the critical value is t = 2.064 The decision would be to: a. for 2.7565 Fail to accept the null hypothesis b. for 2.7565 accept the alternative hypothesis O c. for 2.7565 Reject the alternative hypothesis d. for 2.7565 Reject the null hypothesis

Name: In testing a hypothesis Ho: u 2 3, we found that thetest statistic is
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: In testing a hypothesis Ho: u 2 3, we found that thetest statistic is t = 2.7565 , the critical value is t =%3D2.064 The decision would be to:a. for 2.7565 Fail to accept the null hypothesisb. for 2.7565 accept the alternative hypothesisc. for 2.756

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

If the critical t is ±1.796 and the obtained t is -2.09, what decision would you make regarding the null hypothesis?
If after performing a t-test for comparison of means (alpha= .05) we obtain p=0.0256, what is our conclusion? a. Fail to reject H0 b. Reject H0 c. Reject H1 d. Unable to determine from the information provided
For a hypothesis test, alpha = 0.05 The computed P-Value = 0.011Should H0 be rejected?: Fail to Reject H_0 Reject H_0 What is the correct conclusion? There IS sufficient evidence to reject the Null Hypothesis and accept the alternative. There is NOT sufficient evidence to reject the Null Hypothesis and accept the alternative.
Refer to Exercise 12 in Section 3.2. Assume that τ0 = 50 ± 1 MPa, w = 1.2 ± 0.1 mm, and k= 0.29 ± 0.05 mm−1.a) Estimate τ, and find the uncertainty in the estimate.b) Which would provide the greatest reduction in the uncertainty in τ: reducing the uncertainty in τ0 to 0.1 MPa, reducing the uncertainty in w to 0.01 mm, or reducing the uncertainty in k to 0.025 mm−1?c) A new, somewhat more expensive process would allow both τ0 and w to be measured with negligible uncertainty. Is it worthwhile to implement the process? Explain.
A hypothesis test produces a t statistic of t = +2.19. If the researcher is conducting a two-tailed hypothesis test with α = .05, how large does the sample have to be in order to reject the null hypothesis?
In testing the hypotheses H0: p = 0.5 vs Ha: p <= 0.5, suppose you get a p-value 0.022. Thenyou realize that the one sided alternative is too restrictive and re-do the test with a two sidedalternative Ha : p =/= 0.5.Based on the new p-value, what will be your conclusion ? A. Reject H0 at alpha = 0.01 but not at alpha = 0.05; 0.1.B. Reject H0 at alpha = 0.05 and alpha = 0.1 but not at alpha = 0.01.C. Fail to reject H0 at all the above alpha values.D. Reject H0 at alpha = 0.05 and alpha = 0.01 but not at alpha = 0.1.E. Reject H0 at all the above alpha values.
If the t-computed value is 2.115 and the critical value is 2.423, what will be the decision? a. Reject the null hypothesis. b. Do not reject the null hypothesis. c. Reject both the null and alternative hypotheses. d. Support both the null and alternative hypotheses.
A research report describing the results of a repeated measures t test states: t(22) = 2.91, p < .01.Which option below is consistent with this statement?A. n = 23; the null hypothesis was rejectedB. n = 23; failed to reject the null hypothesisC. n = 22; the null hypothesis was rejectedD. n = 22; failed to reject the null hypothesisE. cannot be determined without knowing the critical value(s)
Refer to Exercise 10 in Section 3.2. Assume that X = 30.0 ± 0.1 Pa, h = 10.0 ± 0.2 mm, and μ = 1.49 Pa · s with negligible uncertainty. a) Estimate V and find the uncertainty in the estimate. b) Which would provide a greater reduction in the uncertainty in V: reducing the uncertainty in τ to 0.01 Pa or reducing the uncertainty in h to 0.1 mm?
Solve An article in the ASCE Journal of Energy Engineering (1999, Vol. 125, pp.59-75) describes a study of the thermal inertia properties of autoclaved aerated concrete used as a building material. Five samples of the material were tested in a structure, and the average interior temperatures (°C) reported were as follows: 23.01, 22.22, 22.04, 22.62, and 22.59. Test that the average interior temperature is equal to 22.5°C using alpha (a) = 0.05. 1.)This problem is a test on what population parameter? a.Variance/ Standard Deviation b.Mean c.Population Proportion d.None of the above 2.)What is the null and alternative 3 points hypothesis? a.Ho / (theta = 22.5) , Ha: (0 # 22.5) b.Ho / (theta > 22.5) , Ha: (0 # 22.5) c.Ho / (theta < 22.5) , Ha: (theta >= 22.5) d.None of the above 3.)What are the Significance level 3 points and type of test? alpha = 0.05 two-tailed alpha = 0.95 two-tailed alpha = 0.95 one-tailed None of the above 4.)What standardized test statistic will…
M1= 37 SS1=360 n1=11 M2= 43 SS2=576 n2=10 Assume two failed test and alpha= .05 What is the critical value?
For a hypothesis test of H0:μ=μ0H0:μ=μ0 against the alternative Ha:μ<μ0Ha:μ<μ0, the z-test statistics is found to be 2.00. This finding is a.significant at neither the 0.01 nor the 0.05 levels. b.significant at the 0.01 level but not at the 0.05 level. c.significant at both the 0.01 and the 0.05 levels. d.not large enough to be considered significant. e.significant at the 0.05 level but not at the 0.01 level.