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In the circuit shown, R = 500 N, L = 0.64 H, C -1 uF, and I = -1 A. The initial voltage drop across the capacitor is 40 V and the initial inductor current is 0.5 A. Find (a) ir(0*); (b) ic(0); (c) diL(0*)/dt; (d) s1, s2; (e) iz(1) for 120; and (f) v(t) for 1 2 0*. An %3D %3D %3D IR 1= 0

In the circuit shown, R = 500 N, L = 0.64 H, C -1 uF, and I = -1 A. The initial voltage drop across the capacitor is 40 V and the initial inductor current is 0.5 A. Find (a) ir(0*); (b) ic(0); (c) diL(0*)/dt; (d) s1, s2; (e) iz(1) for 120; and (f) v(t) for 1 2 0*. An %3D %3D %3D IR 1= 0

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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In the circuit shown, R = 500 N, L = 0.64 H, C 1 µF, and I = -1 A. The initial voltage drop across the capacitor is 40 V and the initial inductor current is 0.5 A. Find (a) ir(0*); (b) ic(0*); (c) di_(0*/dt; (d) s1, s2: (e) iz(t) for t 0; and (f) v(1) for t 0*. Answer: (a) 80 mA; (b) - 1.58 А; (c) 62.5 A/s; (d) (-1000 + j750) rad/s, (-1000 – j750) rad/s; (e) [-1 + e1«"[1.5 cos 750r +2.0833 sin 750r] A, for t 2 0; ic IR (f) e 1000 (40 cos 7501 - 2053.33 sin 750t) V, for t 2 0. VSTOOY
Transcribed Image Text:In the circuit shown, R = 500 N, L = 0.64 H, C 1 µF, and I = -1 A. The initial voltage drop across the capacitor is 40 V and the initial inductor current is 0.5 A. Find (a) ir(0*); (b) ic(0*); (c) di_(0*/dt; (d) s1, s2: (e) iz(t) for t 0; and (f) v(1) for t 0*. Answer: (a) 80 mA; (b) - 1.58 А; (c) 62.5 A/s; (d) (-1000 + j750) rad/s, (-1000 – j750) rad/s; (e) [-1 + e1«"[1.5 cos 750r +2.0833 sin 750r] A, for t 2 0; ic IR (f) e 1000 (40 cos 7501 - 2053.33 sin 750t) V, for t 2 0. VSTOOY
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