pick the answer options provided. In the following triangle, point E is the midpoint of AB, and point D is the midpoint of AC.BEA1CB. The proof is divided into four parts, where the title of each part2Below is the proof that DE =indicates its main purpose.Complete part D of the proof.DECA= 2DAPart A: ProvePick ratio v[Show the steps.]V Pick ratioВАPart B: ProveEA(CD)/(DA)[Show the steps.](CA)/(DA)Part C: Prove ACAB ~ ADAE[Show the steps.](CA)/(CD)CBPart D: Prove DE=СВStatementReasonCBLengths of corresponding sides of similar triangles have equal ratios.(Part C)12DEPick ratio vCB13Substitution (Part A, 12)DE14CB=DEMultiply both sides of the equation byPick expression v(13)n byPick expressionv Pick expression2.DEobleDE(DE)/2

Name: pick the answer options provided. In the following triangle, point E i
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Description: pick the answer options provided. In the following triangle, point E is the midpoint of AB, and point D is the midpoint of AC.BEA1CB. The proof is divided into four parts, where the title of each part2Below is the proof that DE =indicates its main pu

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Math

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In the following triangle, point E is the midpoint of AB, and point D is the midpoint of AC. D E Below is the proof that DE = CB. The proof is divided into four parts, where the title of each part indicates its main purpose. Complete part D of the proof. DE СА Part A: Prove = 2 Pick ratio v %3D DA [Show the steps.] V Pick ratio BA = 2 EA Part B: Prove (CD)/(DA) [Show the steps.] (CA)/(DA) Part C: Prove AC AB ~ ADAE [Show the steps.] (CA)/(CD) =CB Part D: Prove DE = СВ

In the following triangle, point E is the midpoint of AB, and point D is the midpoint of AC. D E Below is the proof that DE = CB. The proof is divided into four parts, where the title of each part indicates its main purpose. Complete part D of the proof. DE СА Part A: Prove = 2 Pick ratio v %3D DA [Show the steps.] V Pick ratio BA = 2 EA Part B: Prove (CD)/(DA) [Show the steps.] (CA)/(DA) Part C: Prove AC AB ~ ADAE [Show the steps.] (CA)/(CD) =CB Part D: Prove DE = СВ

Elementary Geometry for College Students

6th Edition

ISBN:9781285195698

Author:Daniel C. Alexander, Geralyn M. Koeberlein

Publisher:Daniel C. Alexander, Geralyn M. Koeberlein

Chapter6: Circles

Section6.3: Line And Segment Relationships In The Circle

Problem 39E: The center of a circle of radius 2 inches is at a distance of 10 inches from the center of a circle...

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