In the multistep reaction, a bromine in acetic acid solution was used that contained 0.15mL of bromine in 0.3mL of acetic acid. If 0.90mL of this solution was used, how many moles of bromine and acetic acid did was used for this reaction? (Bromine: MW = 159.81 g/mol, density = 3.119 g/mL; Acetic acid: MW = 60.05 g/mol, density = 1.049 g/mL ) %3D
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- If you have 6.61 g of caffeine dissolved in 72.3 mL of water and the extraction coefficient between H2O and CH2Cl2 is 21.51. How many grams of caffeine will extract into the CH2Cl2 layer if you add 87.6 mL?If you have 6.76 g of caffeine dissolved in 57.2 mL of water and the extraction coefficient between H2O and CH2Cl2 is 21.51. How many grams of caffeine will extract into the CH2Cl2 layer if you use 89.9 mL?(Topic: Gravimetry multi-component analysis) The calcium and magnesium in a urine sample were precipitated as oxalates. A mixed precipitate of calcium oxalate and magnesium oxalate resulted and was analyzed by a thermogravimetric procedure. The precipitate mixture was heated to form calcium carbonate and magnesium oxide. This second mixture weighed 0.2504 g. After ignition to form calcium oxide and magnesium oxide, the resulting solid weighed 0.1563 g. What was the mass % of Ca in the mixed oxalate precipitate?
- 5.0 mL of 1-butanol was mixed with 10 mL of HCl. The reaction was put on an ice bath and 4 mL of concentrated sulfuric acid was added. This mixture was refluxed for 45 min and then the product was co-distilled with water using a simple distillation apparatus. Water and the product are immiscible. 1-butanol has a molar mass of 74.12 g/mol, a density of 0.810 g/mL, and a boiling point of 118 C. The product has a molar mass of 92.57 g/mol, a density of 0.880 g/mL, and a boiling point of 78 C. What is the nucleophile in this reaction? What is the role of H2SO4 in this reaction? Calculate the theoretical yield for this reaction. Give your answer in grams. Select the following statements that can be said about the reaction shown.The first goal is to make the oxalic acid standard solution. You measure 1.5232 g of oxalic acid on an analytical balance, add it to a 250-mL volumetric flask and add deionized H2O to a final volume of 250.0 mL. Molar mass of H2C2O4•2H2O = 126.07 g/mol Mass of H2C2O4•2H2O = 1.5232g Volume of H2C2O4•2H2O solution = 250.0mL What is the Molarity H2C2O4 standard solution ?1.063 g of p-acetamidophenol was measured out into a 50 mL round bottom flask along with 8 mL of 1M NaOH in ethanol and a stir bar. This mixture was heated at reflux for 15 min. It was allowed to cool and then 0.80 mL of bromoethane was added to the reaction. The mixture was then heated at reflux for another 15 min. After heating, the solution was poured onto a mixture of ice and water and further cooled on ice and then the solid was collected by vacuum filtration. This solid was then recrystallized from ethanol and water. The final mass of the purified phenacetin was 0.42250 g and it had a melting point of 127 - 130 C. The TLC plate shows (from left to right) pure p-acetamidophenol, the reaction mixture before pouring it on ice/water, phenacetin after recrystallization. The solvent used was a mixture of 80% ethyl acetate and 20% heptane with 0.5% acetic acid added. QUESTION: Using the given TLC plate can you describe the results and what does the TCL plate tell about the purity?
- In a Grignard reaction, 1.4555 g phenyl bromide, 10. g carbon dioxide, 0.5734 g magnesium filings, and 30.2 mL of 6M HCl were used but only 573 mg of benzoic acid were isolated after recrystallization? what was the percent yield for the overall process? Give the answer to the nearest whole number pleaseA concentration of toxic metals in plant tissue is often found by combusting the material in a furnace and then dissolving the ash in concentrated acid. A 0.5124-gram sample of leaves was combusted to ash and transferred to a 150-mL beaker. A 25-mL portion of concentrated HCl was added and the mixture was heated on a hot plate. Three 5-mL portions of concentration HCl were added over approximately 10 minutes with continued heating in between additions. The resulting mixture was cooled to room temperature and filtered into a 50-mL volumetric flask, which was brought to volume using distilled water and mixed well. From this stock solution, a 10-mL portion was pipetted into a clean 50-mL volumetric flask, brought to volume with distilled water, and mixed. This final solution was analyzed and found to contain 12.1 ppm lead. What are the mass percent of lead in the original plant tissue?Scientist 1 analyzed the compounds first then gave it to scientist 2 for the next test. Scientist 2 needs to know the molar mass of the active compound. The concentration of the solution they created is twenty percentw/w from the solid active compound and it has a density of 1.40 grams per millilitre. Ten microliters were taken from this solution and mixed with one hundred ninety microliters of reagent and water. After analyzation, it showed that the compound's concentration is Five times ten raised to negative four M i. Find the concentration of the twenty percentw/w solution. The concentration must be in the form of molarityii. Explain the reason why the concentration of the solution was expressed as %w/w initially?iii. Determine the active compound's molar mass.
- In the results video, a 1% sucrose solution tested negative with Benedict’s solution (part B3). In a separate experiment, 3 M HCl was added to the 1% sucrose solution, allowed to react for 30 minutes, then neutralized with sodium bicarbonate. The resulting solution tested positive with Benedict’s solution. Solution Benedict’s Test 1% sucrose (from B3) - 1% sucrose + HCl (above) + Which solution (the solution from B3 or the one treated with HCl) tested positive for reducing sugars? What are the products of the acid-catalyzed hydrolysis?Measure the mass of 0.400g of Co(NO3)2 + 6H2O and dissolve it in 15mL of distilled or deionized water using a clean beaker Then while using a graduated cylinder, measure out 10.0mL of a prepared 0.10-M Na3PO4 soultion. Determine which compound Na3PO4 or Co(NO3)2 *6H2O will be the limliting reagent. Then detrimine the theiretical yeildLead nitrate Stock Solution— Dissolve 159.8 mg of lead nitrate in 100 mL of water to which has been added 1 mL of nitric acid, then dilute with water to 1000 mL. Standard Lead Solution— On the day of use, dilute 10.0 mL of Lead Nitrate Stock Solution with water to 100.0 mL. Each mL of Standard Lead Solution contains how many µg of lead? Standard Preparation— Into a 50-mL color-comparison tube pipet 2 mL of Standard Lead Solution, and dilute with water to 40 mL, and mix. Test Preparation— Into a 50-mL color-comparison tube dissolve 1.0g ascorbic acid (mol wt 176.12) in 25 mL of water, dilute with water to 40 mL, and mix. Procedure— To each of the two tubes containing the Standard Preparation, the Test Preparation, add 2 mL of pH 3.5 Acetate Buffer, then add 1.2 mL of thioacetamide–glycerin base TS, dilute with water to 50 mL. Mix, allow to stand for 2 minutes, and view downward over a white surface. The color of the solution from the Test Preparation is not darker than that of the…