In the second propogation step, why is another Cl-Cl used? Why can't we just use the second Cl radical created from the initiation step? a. Initiation step: generates reactivate intermediate.(radical electrons++ photon (hv):C1-Cl:b. Propagation steps: reactivate intermediate reacts with stable moleculeproduct and another reactive intermediate.First propagation stepHH-C-H-+Cl:H-C:+H-CIHHmethanechlorine atommethyl radicalhydrogen chlorideSecond propagation stepHHH-C:+Cl"CiН-С—СІ+Cl·Hmethyl radicalchlorine moleculechloromethanechlorine atom

The second propagation, a methyl radical reacts with the Cl2 to give CH3Cl and a Cl radical.

Answered: In the second propogation step, why is…

In the second propogation step, why is another Cl-Cl used? Why can't we just use the second Cl radical created from the initiation step?

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter16: Chemistry Of Benzene: Electrophilic Aromatic Substitution

Section16.8: Oxidation Of Aromatic Compounds

Problem 19P

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Question

In the second propogation step, why is another Cl-Cl used? Why can't we just use the second Cl radical created from the initiation step?

a. Initiation step: generates reactivate intermediate.
(radical electrons
+
+ photon (hv)
:C1-
Cl:
b. Propagation steps: reactivate intermediate reacts with stable molecule
product and another reactive intermediate.
First propagation step
H
H-C
-H-
+
Cl:
H-C:
+
H-CI
H
H
methane
chlorine atom
methyl radical
hydrogen chloride
Second propagation step
H
H
H-C:
+
Cl"Ci
Н-С—СІ
+
Cl·
H
methyl radical
chlorine molecule
chloromethane
chlorine atom

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