included a picture of someone who solved but they were mostly incorrect. Please do not answer if the solution set I provided with the incorrect answers was you. I appreciate the attempt, but the solutions for 3, 4, 5, 6, 8, 9, 10, 12 were marked wrong, so unless you have different answers, please do not submit the same incorrect solution set. The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (1) If the mass center G is set as the origin (datum), the gravitational

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question

Please answer 3, 4, 5, 6, 8, 9, 10, 12

1 is 0, 2 is 0, 7 is point A, 11 is 2. 

I included a picture of someone who solved but they were mostly incorrect. Please do not answer if the solution set I provided with the incorrect answers was you. I appreciate the attempt, but the solutions for 3, 4, 5, 6, 8, 9, 10, 12 were marked wrong, so unless you have different answers, please do not submit the same incorrect solution set.

The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m.

(1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is___  (two decimal places)

(2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is___  (two decimal places)

(3) The stretched spring length of the spring at the state 1 is________(m) (two decimal places)

(4) The elastic potential energy at the potion 1 is_______(N·m) (two decimal places)

(5) The stretched spring length of the spring at the state 2 is _______(m) (two decimal places)

(6) The elastic potential energy the state 2 is ___ (N·m ) (two decimal places)

(7) The instantaneous center of zero velocity (IC) is

(8) The mass moment of inertial about the mass center G is I=_________(kg·m) (two decimal places)

(9) The mass moment of inertial about the IC center is IIC =_________(kg·m) (two decimal places)

(10) The kinetic energy at the state1?________ (N·m) (two decimal places)

(11) The angular velocity at the state 2?_______(rad/s) (two decimal places)

(12) The kinetic energy at the state 2?______ (N·m) (two decimal places)

//
44
L2
J-
State 2
Li
State 1
datum
Transcribed Image Text:// 44 L2 J- State 2 Li State 1 datum
So, hpo
state 1).
datum is at contre b
✓
4₁ = mign₁ = 20 (9.81) (0) (U₁ = 0.00J
растит
D
trum is at control a
:: U₂ = mgh₂
AL₁= 2₁-20
5012₂=0
20 (9.81) (0) 2. JU₂ = 0.00 J
24-1=13m
elastic energy.
at State I
(KE) KAL = (2) (3)² = 95
8 AL ₂ = 4₂-L0 = 3.464-1 = √2.466m
elastic energy at state 2
(KEN) = 2 × 0²² = {(2) (12.464)² = ■ ■
2
of The
8
The IC of zess velocity at
$IJL=
Ia = #my² = ± (20) (0.6) ²
:: IG= 13.6 kg m ²
IG + my² = 3.6+ (20) (0.6)²
= II₁ = 10.8 kgm²
m (0)² - 19 J
point A
6.07135
10) (Kev) = {mv ²3 (1) / m2 (0)² =
+9
(KEN) = 1 mv ₂ ² + £ 1 W³² = . / Ise W² = 5.4 w²0
KE₁ + U₁ = KĘ₂₁+U₂ =)
0+9+0= (KE) ₂2 + 6.0713 +0 =).
KE₂ = 5.40² + 6.0713
|KG₂ = 95
(KEN).
= 2.928 J
540²
=
2W₁ = 0.7364 radls
Transcribed Image Text:So, hpo state 1). datum is at contre b ✓ 4₁ = mign₁ = 20 (9.81) (0) (U₁ = 0.00J растит D trum is at control a :: U₂ = mgh₂ AL₁= 2₁-20 5012₂=0 20 (9.81) (0) 2. JU₂ = 0.00 J 24-1=13m elastic energy. at State I (KE) KAL = (2) (3)² = 95 8 AL ₂ = 4₂-L0 = 3.464-1 = √2.466m elastic energy at state 2 (KEN) = 2 × 0²² = {(2) (12.464)² = ■ ■ 2 of The 8 The IC of zess velocity at $IJL= Ia = #my² = ± (20) (0.6) ² :: IG= 13.6 kg m ² IG + my² = 3.6+ (20) (0.6)² = II₁ = 10.8 kgm² m (0)² - 19 J point A 6.07135 10) (Kev) = {mv ²3 (1) / m2 (0)² = +9 (KEN) = 1 mv ₂ ² + £ 1 W³² = . / Ise W² = 5.4 w²0 KE₁ + U₁ = KĘ₂₁+U₂ =) 0+9+0= (KE) ₂2 + 6.0713 +0 =). KE₂ = 5.40² + 6.0713 |KG₂ = 95 (KEN). = 2.928 J 540² = 2W₁ = 0.7364 radls
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Knowledge Booster
Free Undamped Vibrations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY